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3 years ago

11

Enlarge shape s by scale factor 1/3 centre (0,3)

2 answers:

Dima020 [189]3 years ago

8 0

Answer:

Picture attached :)

Step-by-step explanation:

Draw straight lines from the corner of the shape to the point at (0,3) - now you have the outline of where the new shape should go. Now divide the number of squares on each side by 3. This is easy as the shape uses multiples of 3. Then find within the lines where the shape fits. This is how I did it, hope it helps,

vovikov84 [41]3 years ago

5 0

Take all the 6 points on the edges of that shape then multiple each single individual point by 1/3 and hopefully you get your new points and then just connect the points and you will eventually get your new shape

that’s all I think hope that helps

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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

4 years ago

When 3(2x + 9) = 4x - 7 is solved for X, the solution is<br> 1<br> 3.<br> is 17<br> 4<br> xs-17

lyudmila [28]

$\\ \sf\longmapsto 3(2x+9)=4x-7$

$\\ \sf\longmapsto 6x+27=4x-7$

$\\ \sf\longmapsto 6x-4x=-7-27$

$\\ \sf\longmapsto 2x=-34$

$\\ \sf\longmapsto x=17$

8 0

3 years ago

Read 2 more answers

What is the value of y? NU=9, NM= 3, MT= 6, TN= y

nevsk [136]

Answer:

6 $\sqrt{3}$

Step-by-step explanation:

We have to use Pythagoras' identity twice to find y

The square on the hypotenuse is equal to the sum of the squares on the other two sides.

In right triangle MUT to find TU

TU² + 3² = 6², that is

TU² + 9 = 36 ( subtract 9 from both sides )

TU = 27 ( take the square root of both sides )

TU = $\sqrt{27}$ = $\sqrt{9(3)}$ = 3 $\sqrt{3}$

In right triangle NUT to find y

y² = 9² + (3 $\sqrt{3}$ )² = 81 + 27 = 108 ( take the square root of both sides )

y = $\sqrt{108}$ = $\sqrt{36(3)}$ = 6 $\sqrt{3}$

3 0

3 years ago

Help me please with this

Elis [28]

Answer:

$155.43 in^3$

Step-by-step explanation:

base*hight

$=> \pi r^2 = 3^2*\pi =9*3.14=28.26$

$=> B*H=28.26*5.5=155.43\\$

5 0

3 years ago

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A cake recipe calls for two eggs per cake. Sydney used 20 eggs in this recipe for a bake sale. How many cakes did she bake?

Alex787 [66]

20 / 2 = 10

Sydney baked 10 cakes :D

8 0

4 years ago

Read 2 more answers