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nika2105 [10]
3 years ago
13

If a ants can dig b tunnels in c hours, how many tunnels can b ants dig in a hours?

Mathematics
1 answer:
Lilit [14]3 years ago
7 0

9514 1404 393

Answer:

  b²/c tunnels

Step-by-step explanation:

The number of tunnels per ant-hour is ...

  b/(ac)

Multiplying that by the new number of ant-hours, we have ...

  (b/(ac))(ab) = b²/c . . . . tunnels

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Describe how to add or subtract rational expressions with like denominators.
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Answer:if the bottoms are the same keep the the sme

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Which out of these numbers has the same absolute value as one another and please help I don't really understand absolute value
Mariulka [41]

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Step-by-step explanation:Absolute value is a number's distance away from zero. For example, on a number line, -9 is 9 spaces away from zero. So, the absolut value is 9. Similarly, the number 9 is also 9 spaces from zero, so the absolute value would be 9. 9 and -9 both have an absolute value of 9. I hope this is helpful!


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Help please! It's a quiz. will mark brainliest for correct answer!
yarga [219]

Answer:

you first start by making your equation: 45 +.25x = 70 +.15x. then subtract .15x from both sides. it should look like 45 +.10x = 70. subtract 45 from both sides then you get .10x = 25. divide 10 to both sides and you get 250. so the two companies will be the same at 250 texts.

Step-by-step explanation:

8 0
3 years ago
Jackson eats 3/4 cup of food in the morning and 3/4 cup of food at night. How many cups of food does Jackson eat in 5 days
Sonja [21]

Answer:

Jackson eats 15/2 cups of food in 5 days.

Step-by-step explanation:

If Jackson eats 3/4 of food in the morning and at night then he eats 3/2 of food a day or 1.5 cups of food a day.

1.5*5 = 7.5

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5 0
2 years ago
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The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
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