1. A Texas House representative proposed placing solar panels on all public schools to increase
1 answer:
Answer:
Yes, at 5% significant level, there is sufficient statistical evidence to purchase the panels
Step-by-step explanation:
The given parameters are;
The acceptable efficiency, μ > 18% = 0.18
The number of panels in the sample, n = 32 panels
The mean efficiency of the panels, = 0.182
The standard deviation of the sample, s = 0.006
The significance level of the test, α = 5%
The null hypothesis; H₀ p ≤ 0.18%
Given that the population standard deviation is unknown, we use the t-test statistic which is given as follows;
Plugging in the values we get;
The degrees of freedom, df = n - 1 = 32 - 1 = 31 (a df value of 30 is used as an approximation to obtain the value from the t-table)
The critical t at 5% significance level t = 1.697
Therefore, given that the test statistic is larger than the critical t, we reject the null hypothesis, and there is sufficient statistical evidence that efficiency of the panels is larger than 18% and therefore, we should purchase the panels
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The complete question in the attached figure
we have that
for c=5 and n=20------------> n*c=20*5=100
for c=2.5 and n=40------------> n*c=40*2.5=100
for c=2 and n=50------------> n*c=50*2=100
for c=1.25 and n=80------------> n*c=80*1.25=100
therefore
<span>the function that models the data is n*c=100
</span>
the answer is nc=100
we have that
for c=5 and n=20------------> n*c=20*5=100
for c=2.5 and n=40------------> n*c=40*2.5=100
for c=2 and n=50------------> n*c=50*2=100
for c=1.25 and n=80------------> n*c=80*1.25=100
therefore
<span>the function that models the data is n*c=100
</span>
the answer is nc=100