Answer: 51
Step-by-step explanation:
From the question, we are informed that there are 2601 students in a school and that the teacher want them to stand in rows and columns.
Since the number of the row and column are equal, thus will go thus:
Let the number of row and column be represented by y. Therefore,
y × y = 2601
y² = 2601
y = ✓2601
y = 51
Therefore the rows and columns must be 51 each.
Answer:
x=0
y=7
Divide 6x-4y=-28 by -2..... -3x+2y=14
3x+5y=35
-3x+2y=14
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7y=49
6x-4*7=-28
solutions at -1 and 11
(-b ± √b²-4ac) / 2a
in this problem, a = 1, b = -10, c = -11
(10±√100-4(-1)(-11)) / 2(1) =
(10 + √144) / 2 = 22/2 = 11
(10 - √144) / 2 = -2 / 2 = -1
A is correct
You have to find the rate of change for each one.
Divide the price with the amount
Hope this helps!
4c(-a+b+c) - 3a( a+b+c) - 2b( a-b+c)
