(2x + 3y - 4) – (5x + 2)
1 answer:
You might be interested in
Answer:
third side = 9
Step-by-step explanation:
Using Pythagoras' identity on the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let the third side be x, then
x² + 40² = 41², that is
x² + 1600 = 1681 ( subtract 1600 from both sides )
x² = 81 ( take the square root of both sides )
x = = 9
The third side is 9
Answer:
Step-by-step explanation:
Probability of getting a 7 + Probability of not getting a 7 = 1.
Odds against drawing a 7 = Probability of not getting a 7.
We could calculate the probability of getting a 7 and subtract 1 from it to get the answer.
There a four sevens in a deck of card, one of each kind.
Probability of getting a 7 =
P(not getting a 7)
Each time you fold a paper it will double the amount of parts. When you think about it, it's just multiplying by 2 a bunch of times.
One fold is 2 times 1, which is 2.
The second fold is 2 times 2, which is 4.
The third fold is 4 times 2, which is 8.
Using this process, we can simplify that into exponents. If the amount of times you fold is x and the parts double for each fold, then the amount of parts can be represented by:
So if the amount of parts is given and we need the amount of folds, just keep doubling until you get to 64. The amount of times you doubled is the number of times Sylvie folded.
Later you will learn that the opposite of an exponent is a logarithm, which would look like this:
But don't worry about that yet.
One fold is 2 times 1, which is 2.
The second fold is 2 times 2, which is 4.
The third fold is 4 times 2, which is 8.
Using this process, we can simplify that into exponents. If the amount of times you fold is x and the parts double for each fold, then the amount of parts can be represented by:
So if the amount of parts is given and we need the amount of folds, just keep doubling until you get to 64. The amount of times you doubled is the number of times Sylvie folded.
Later you will learn that the opposite of an exponent is a logarithm, which would look like this:
But don't worry about that yet.