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Using the completing the square method, for the equation, we have the zeros as <u>x = √26 + 4 and x = 4 - √26</u>
<h3>How can the zeros be found using completing the square method?</h3>The given equation is presented as follows
Which, by completing the square, gives;
The zeros of the equation;
are;
Learn more about completing the square here:
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$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$