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likoan [24]
2 years ago
13

Christopher rides his bike to and from school every day. The total distance he

Mathematics
1 answer:
Vitek1552 [10]2 years ago
8 0

Answer

5 miles

Step-by-step explanation:

If he rides his bike one mile each day school to home each day its going to be 1 mile per day so if its 5 days it is 5 miles

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Kelly has a rectangular fish aquarium that
Hoochie [10]
Volume = 18x8x12
= 1728
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HELP PLS’ Suppose you roll a die. Find the probability of the given event. Simplify your answer.
NikAS [45]

The answer is 2) 2/3

7 0
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What method do i use to solve this?
skelet666 [1.2K]
Answer: x=20
all angles in the triangle are 180 degree, so:
2x+3x+4x=180
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8 0
3 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
Suppose that 44 identical red wooden blocks and 99 identical white wooden blocks are to be​ stacked, one on top of​ another, to
kirza4 [7]

44 identical red wooden blocks can be arranged in 44! ways

99 identical white wooden blocks can be arranged in 99! Ways

If the 44 red blocks and the 99 white blocks are to be stacked on top of one another, the number of different color patterns that can​ result = 44! x 99!

 

44! = 2.65827157 x 10^54

99! = 9.33262154 x 10^155

44! x 99! = 2.48086426 x 10^210

 

Therefore, 2.48086426 x 10^210 different color patterns can ​result

7 0
3 years ago
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