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3 years ago

Solve for x. 8 - 2x = 5(x - 4) X = [?] Enter

Mathematics

2 answers:

belka [17]3 years ago

5 0

Answer: x=4

given equation: 8 - 2x= 5(x-4)

STEP 1: distribute the 5 with ONLY the parenthesis which is (x-4)

so it will be 5x-20 (-20 because 5 x -4= -20)

Now the equation is 8 - 2x= 5x - 20

STEP 2: ADD 20 on both SIDES

8+20= 28

New equation: 28 - 2x= 5x

STEP 3: ADD 2x on both sides 2x+5x= 7x

STEP 4: Now divide 28 by 7

28/7= 4

Therefor x= 4

Oduvanchick [21]3 years ago

4 0

Answer:

Step-by-step explanation:

8-2x=5(x-4)

8-2x=5x-20

28=7x

x=4

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The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12

Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

$P(x)=-12x^2+120x$

To find:

The current that will produce the maximum power.

Solution:

We have,

$P(x)=-12x^2+120x$

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, a=-12 and b=120. So,

$-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}$

$-\dfrac{b}{2a}=-\dfrac{120}{-24}$

$-\dfrac{b}{2a}=5$

Putting x=5 in the given function, we get

$P(5)=-12(5)^2+120(5)$

$P(5)=-12(25)+600$

$P(5)=-300+600$

$P(5)=300$

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0

3 years ago

Does anyone know the answer to this!?

PolarNik [594]

Answer:

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

$x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},$

where

$|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

So,

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

4 0

3 years ago

Solve the following equation system by graphing X-Y=4 X+Y=2 What is the solution?

AfilCa [17]

X-Y=4,
X+Y=2
-------------add
2x = 6
x = 3

X - Y =4
3 - Y = 4
Y = 3 - 4
Y = -1

solution (3 , -1)

4 0

3 years ago

Dillon deposited 3/4 of his paycheck into the bank. The deposit slip shows how much he deposited. ($46.50) Weite and solve an eq

Sliva [168]

3/4 is 75%. So 0.75x = $46.50, x = $62.00

6 0

3 years ago

Given the sample 4, −2, −6, 19, 6, add one more sample value that will neither change the mean nor the variance. Round to two de

DedPeter [7]

Answer:

Cannot create sample

Step-by-step explanation:

We are given the following in the question:

4, -2, -6, 19, 6

Formula:

$\text{Variance} = \displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{21}{5} = 4.2$

Sum of squares of differences = 0.04 + 38.44 + 104.04 + 219.04 + 3.24 = 364.8

$s^2 = \dfrac{364.8}{4}} = 91.2$

If we add an observation equal to the mean of given sample, then the mean and of new sample will not change.

New sample:

4, -2, -6, 19, 6, 4.2

$Mean =\displaystyle\frac{25.2}{6} = 4.2$

Sum of squares of differences = 0.04 + 38.44 + 104.04 + 219.04 + 3.24 + 0 = 364.8

$s^2 = \dfrac{364.8}{5}} = 72.96$

Thus, the variance of new sample changes.

Thus, it is not possible to create a sample.

5 0

3 years ago