Have to find measure of angle A!! Please help ASAP, I need to show my work!!

Solve the equation.Check your solution<br><br>1.5x = 3

PIT_PIT [208]

Divide both sides by 1.5

1.5x = 3

x = 2

Check the equation by plugging in the 2.

1.5(2) = 3

3 = 3

3 0

3 years ago

Amy makes a rectangular poster with an area of 21+28m square inches. The width of the poster is 7 inches as shown in the followi

Lesechka [4]

You could use simple factoring to solve this. You would factor out a 7 and then have

7(3+4m) = A

l x w = A

w= 3 +4m

8 0

3 years ago

The two legs (labeled x) of the right triangle below have equal length. If the hypotenuse has length 5√2 , solve for x.

leonid [27]

Answer:

x=5

Step-by-step explanation:

Other than using the plain special aspect of a 45-45-90 triangle where the legs are x, x, and x√2, you can solve for this.

Since the two legs have equal length, they are both x. Using the pythagorean theorem:

(x^2)+(x^2)=50 (Because 5 squared is 25 and √2 squared is 2, multiplying them gives you 50).

You can add (x^2) and (x^2) because they are the same terms (x squared).

Simplifying like so gives you:

2x^2=50

Dividing by two on both sides:

x^2=25

Taking the square root of both sides:

x=5

6 0

3 years ago

Angela borrowed $1,500. She will Pay back this amount in 12 equal and payments. What is the amount of each payment Angela will m

lana [24]

Answer:

$120

Step-by-step explanation:

She borrowed$1500 and has to pay 12equal.

To Know the amount paid each,it will be$1500/12

And the answer is$125

Which means she will be paying$125 each

7 0

3 years ago

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{670 - 660}{9}$

$Z = 1.11$

$Z = 1.11$ has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0

2 years ago