<span>1. </span><span>So we have the system of
equation. (4, -3)
let’s create another system of equation.
Let a = 4
and Let b = -3
First equation
=> Let’s pick any numbers to be used. Let’s have number 5
=> 5a + 5b
=> 5 (4) + 5 (-3)
=> 20 + (-15)
negative and positive is equals to negative
=> 20 – 15
=> 5 (this the first value of our equation, let this be the value of X)
Second
=> Pick another number, Let’s have 6
=> 6a + 6b
=> 6 (4) + 6 (-3)
=> 24 + (-18)
=> 24 – 18
=> 6 (this is the value of our second equation, let this value be Y)
Now, we have (A, B) = (4, -3) and (X, Y) = (5,6)</span>
I think it’s B sorry if I’m wrong
We know that x^m * x^n = x^( m + n ).
And the seventh root of x to the fifth power is:
![\sqrt[7]{ x^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%20x%5E%7B5%7D%20%7D%20)
Therefore:
![\sqrt[7]{ x^{5} } * \sqrt[7]{ x^{5} } = \\ = \sqrt[7]{ x^{5} * x^{5} }= \\ = \sqrt[7]{ x^{10} }= \sqrt[7]{ x^{7} }* \sqrt[7]{ x^{3} }=x* \sqrt[7]{ x^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%20x%5E%7B5%7D%20%7D%20%2A%20%20%5Csqrt%5B7%5D%7B%20x%5E%7B5%7D%20%7D%20%3D%20%5C%5C%20%3D%20%5Csqrt%5B7%5D%7B%20x%5E%7B5%7D%20%2A%20x%5E%7B5%7D%20%7D%3D%20%5C%5C%20%3D%20%5Csqrt%5B7%5D%7B%20x%5E%7B10%7D%20%7D%3D%20%5Csqrt%5B7%5D%7B%20x%5E%7B7%7D%20%7D%2A%20%5Csqrt%5B7%5D%7B%20x%5E%7B3%7D%20%7D%3Dx%2A%20%5Csqrt%5B7%5D%7B%20x%5E%7B3%7D%20%7D%20%20%20%20%20)
Answer:
D ) x times the seventh root of x cubed.
Answer:
D. 48
Step-by-step explanation:
We don't know the numbers of coupons sent to existing members and to potential members, but we know a relationship between the number.
They sent 5 times as many coupons to potential members as they did to existing members.
Let x = number of coupons sent to existing members.
Then 5x = number of coupons sent to potential members.
The total number of coupons sent was x + 5x = 6x
The total number of coupons sent was 288.
Therefore, 6x must equal 288 giving us an equation with a single variable.
6x = 288
x = 48
Answer: 48
