You simply put 40 over a hundred and 55 over n (which is the number were trying to find) so you do cross multiplication. 55 times a hundred and after you get the answer. You divide it by 40 and should get 137.5.
the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.
the input goes to the 1st machine and the output of that goes to the 2nd machine.
a)
if she uses and input of 6 on the 2nd one, the result will be 6² - 6 = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.
b)
clearly we can never get an output of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.
let's check something, we need a -5 on the 2nd, so
![\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7Bfinal~out%20put%7D%7B%5Cstackrel%7By%7D%7B-5%7D%7D%3Dx%5E2-6%5Cimplies%201%3Dx%5E2%5Cimplies%20%5Csqrt%7B1%7D%3Dx%5Cimplies%201%3Dx)
so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.
![\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7Bfirst~out%20put%7D%7B%5Cstackrel%7By%7D%7B1%7D%7D%3D%5Csqrt%7Bx-5%7D%5Cimplies%201%5E2%3Dx-5%5Cimplies%201%3Dx-5%5Cimplies%206%3Dx)
so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.
![\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bfirst~machine%7D%7By%3D%5Csqrt%7B%5Cboxed%7B6%7D-5%7D%7D%5Cimplies%20y%3D%5Csqrt%7B1%7D%5Cimplies%20y%3D1%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Bsecond~machine%7D%7By%20%3D%20%5Cboxed%7B1%7D%5E2-6%7D%5Cimplies%20y%20%3D%201-6%5Cimplies%20y%20%3D%20-5)
Original Perimeter = 2.5 + 2.5 + 1.5 + 1.5 = 8
The longer dimension is 2.5 as 2.5 > 1.5To make 2.5 into 10, we must multiply by 4For the smaller length, we must also multiply by 41.5 x 4 = 6
New Perimeter = 10 + 10 + 6 + 6 = 32
Now find the difference between the old and the new perimeter32 - 8 = 24
<em>*No units were specified - if included, remember to put them in your answer.</em>
Answer:
what are you doing
Step-by-step explanation: