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AleksandrR [38]
3 years ago
14

Krusty Krabs Breath Mints Mr. Krabs created a secret ingredient for a breath mint that he thinks will “cure” the bad breath peop

le get from eating crabby patties at the Krusty Krab. He asked 100 customers with a history of bad breath to try his new breath mint. He had fifty customers (Group A) eat a breath mint after they finished eating a crabby patty. The other fifty (Group B) also received a breath mint after they finished the sandwich; however, it was just a regular breath mint and did not have the secret ingredient. Both groups were told that they were getting the breath mint that would cure their bad breath. Two hours after eating the crabby patties, thirty customers in Group A and ten customers in Group B reported having better breath than they normally had after eating crabby patties.
Identify the control "group" (C), the independent variable (IV), and the dependent variable (DV) in your answer.
Chemistry
1 answer:
Liula [17]3 years ago
7 0
He sponge bob. Kristin craf
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Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular
mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

\frac{actual yield}{theoretical yield} .100

Where the actual yield is <em>how much product was obtained</em>, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is <em>how much product could be obtained with the given reactants theoretically</em>, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

 Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

 moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

 Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

\frac{actual yield}{theoretical yield} .100

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

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What are the two main categories of energy?
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Kinetic and potential energy
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Classify the possible combinations of signs for a reaction's ΔH and ΔS values by the resulting spontaneity
FinnZ [79.3K]

Answer :

(A) ΔH is positive and ΔS is negative  → (2) Spontaneous in reverse at all temperatures

(B) ΔH is positive and ΔS is positive  → (3) Spontaneous as written above a certain temperature

(C) ΔH is negative and ΔS is positive  → (1) Spontaneous as written at all temperatures

(D) ΔH negative and ΔS is negative → (4) Spontaneous as written below a certain temperature

Explanation :

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

\Delta H = enthalpy change

\Delta S = entropy change  

T = temperature in Kelvin

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

(A) ΔH is positive and ΔS is negative.

\Delta G=\Delta H-T\Delta S

\Delta G=(+ve)-T(-ve)

\Delta G=(+ve)

The reaction is non-spontaneous at all temperatures or spontaneous in reverse at all temperatures.

(B) ΔH is positive and ΔS is positive.

\Delta G=\Delta H-T\Delta S

\Delta G=(+ve)-T(+ve)

\Delta G=(+ve)    (at low temperature)   (non-spontaneous)

\Delta G=(-ve)    (at high temperature)   (spontaneous)

The reaction is spontaneous as written above a certain temperature.

(C) ΔH is negative and ΔS is positive.

\Delta G=\Delta H-T\Delta S

\Delta G=(-ve)-T(+ve)

\Delta G=(-ve)

The reaction is spontaneous as written at all temperatures

(D) ΔH is negative and ΔS is negative.

\Delta G=\Delta H-T\Delta S

\Delta G=(-ve)-T(-ve)

\Delta G=(+ve)    (at high temperature)   (non-spontaneous)

\Delta G=(-ve)    (at low temperature)   (spontaneous)

The reaction is spontaneous as written below a certain temperature.

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When electrons move closer to a more electronegative atom, what happens? the more electronegative atom is _____?
djverab [1.8K]
<span>The more electronegative atom is reduced.</span>
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4 years ago
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