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pentagon [3]
3 years ago
14

An atom has a charge of +1 in its nucleus.

Chemistry
1 answer:
Fofino [41]3 years ago
7 0
To gain an electron from any atom
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Which state of matter expands when heated and is easy to compress? gas solid liquid
butalik [34]

Answer:

gas

Explanation:

The gas molecules are far apart and as such, when heated they gain more kinetic energy thereby colliding with one another and with the wall of the container thereby exerting pressure and also they can be compressed by reducing the distance between between the molecules.

8 0
3 years ago
If a bar of motilium cost .0.2 dollars how much will 200 bars cost
lorasvet [3.4K]

Answer: 40

Explanation: 0.2 x 200

3 0
3 years ago
How many moles are in 7.2 x 10^23 carbon molecules?
choli [55]

Explanation:

It is known that in 1 mole there are 6.023 \times 10^{23} atoms or molecules.

It is given that there are 7.2 \times 10^{23} carbon molecules. Therefore, calculate the moles as follows.

     Number of moles = \frac{7.2 \times 10^{23} molecules}{6.023 \times 10^{23} molecules/mol}

                                   = 1.196 mol

Thus, we can conclude that there are 1.196 mol in 7.2 \times 10^{23} carbon molecules.

7 0
3 years ago
Which of the following equations is balanced correctly and has the correct products for the reactants RbNO3 and BeF2?
Pavel [41]

Answer:

2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction

Explanation:

2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction

Rb is a +1 cation, NO3 is a -1 anion, Be is a +2 cation and F is a -1 anion.

In writing an ionic compound the charge of the cation becomes the subscript of the anion and the charge of the anion becomes the subscript of the cation.  

So the ionic compound formed between Be2+ and F- is BeF2. The ionic compound formed between Be2+ and NO3- is Be(NO₃)₂.  

As there are two NO₃ on the product side it is balanced by writing a 2 coefficient before RbNO₃ on the reactant side.  

And as there are two F on the reactant side it is balanced by writing a 2 coefficient before RbF on the product side.  

5 0
3 years ago
How many atoms are present in 3.1 moles of copper?
ozzi

Answer:

<h2>1.8662 × 10²⁴ atoms</h2>

Explanation:

The number of atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 3.1 × 6.02 × 10²³

We have the final answer as

<h3>1.8662 × 10²⁴ atoms</h3>

Hope this helps you

8 0
3 years ago
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