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I am Lyosha [343]
3 years ago
14

What’s the volume and surface area

Mathematics
1 answer:
KiRa [710]3 years ago
6 0

Surface area and volume are calculated for any three-dimensional geometrical shape. The surface area of any given object is the area or region occupied by the surface of the object. Whereas volume is the amount of space available in an object.

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A shirt is priced at $24.95. If you have a coupon for 30% off, how much does the shirt cost after the coupon is applied?
kompoz [17]
It should be About $7.49
7 0
3 years ago
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What is the volume of this?
luda_lava [24]
2079 cubic meters because V=Bh so you multiply 21 and 11 to get B then you multiply B and 9 (h) to get your answer.
7 0
4 years ago
3x+4y=2 4x-4y=12 by using elimination
Sidana [21]
(+3x+4y=2)
(+4x-4y=12)
-----------------
7x = 14
-----------------
7
X=2

3(2)+4y=2
6+4y=2
4y=-4
Y=-1.
Or you can plug x into the other equation.

4(2)-4y=12
8-4y=12
-4y=4
Y=-1.

8 0
3 years ago
The vertices of a triangle are A (2,5) B (1,2) and C (3,1) . Find the coordinates of the image after a dilation with respect to
telo118 [61]

K=2

  • A'=2(2.5)=(4,10)
  • B'=2(1,2)=(2,4)
  • C'=2(3,1)=(6,2)

Translation of 2 units left means change in x

  • A''=(4-2,10)=(2,10)
  • B"=(2-2,4)=(0,4)
  • C"=(6-2,2)=(4,2)

Translation of 1 units up means change in y

  • A'''=(2,10+1)=(2,11)
  • B'''=(0,4+1)=(0,5)
  • C'''=(4,2+1)=(4,3)
5 0
2 years ago
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In equilateral ΔABC, AD, BE, and CF are medians. If FO = 4, then AE = A) 4 B) 4 3 C) 8 D) 12
vampirchik [111]

Firstly, we need to draw triangle

we know that

O is a centroid

and centroid divides median into 2:1

so,

\frac{CO}{FO} =\frac{2}{1}

we have FO=4

so, we can plug it

\frac{CO}{4} =\frac{2}{1}

CO=8

now, we can find CF

CF=OC+FO

CF=8+4

CF=12

now, we can see triangle ACF is a right angled triangle

so, we can use pythagoras theorem

x^2=(\frac{x}{2} )^2+12^2

now, we can solve for x

\frac{3x^2}{4}=144

x^2=192

x=8\sqrt{3}

Since, it is equilateral triangle

so,

AC=x=8\sqrt{3}

we know that

E is a mid-point

so,

AE=\frac{AC}{2}

now, we can plug values

AE=\frac{8\sqrt{3}}{2}

AE=4\sqrt{3}................Answer


5 0
3 years ago
Read 2 more answers
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