Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
The variable would be m Lol
I am assuming when you write 27x5 u mean "27 times x to the power of 5".
therefore, your answer is 9x3-11x2-7x
100-20 round the last numbers so they have a 0 at the end so 4 or under is 0 and 5 or higher is 10 so 100 - 20 is 80