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Neporo4naja [7]
2 years ago
11

The graphs of functions f(x) and g(x) = f(x) + k are shown below what is the value of k?

Mathematics
2 answers:
natali 33 [55]2 years ago
5 0

Answer:

k = 2

Step-by-step explanation:

f(x) and g(x) = f(x) + k

G(x) is the function f(x) moved up k units

G(x) is moved up 2 units so k is 2

Viktor [21]2 years ago
4 0

Answer:

The answer is k = 2. The value of k is 2.

Step-by-step explanation:

I hope this answers your question :) Have a great day :)

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Answer:

D . (486 – 9 + 6) + (33 × 2)

Step-by-step explanation:

Which expression is equivalent to 486 – 9 + 6 + 33 × 2?

486 – 9 + 6 + 33 × 2

486 – 9 + 6 + 66

477 + 6 + 66

549

D . (486 – 9 + 6) + (33 × 2)

      477 + 6 + 66

               549

Hope this helps!

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Olivia has a family of 15 people. 9 of them are female. If
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wouldn't that just be 1/15?

Step-by-step explanation:

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In D

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Find irrational number between 5, 25 and 5, 26​
iragen [17]

Answer:

The answer is 2.5135145

Step-by-step explanation:

  • The irrational number between 5,25 and 5,26
  • 2.5135145...
  • The number is non-terminating and non-recurring. Hence, it is an irrational number.
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antiseptic1488 [7]

Answer:

\sf -11+7\sqrt{2}

Step-by-step explanation:

Given expression:

\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }

Rewrite 32 as 16 · 2:

\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }

Apply radical rule \sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }

As \sf \sqrt{16}=4:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }

Multiply by the conjugate:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }

\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}

\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}

As \sf \sqrt{2}\sqrt{2}=\sqrt{4}=2:

\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}

\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}

\sf \implies \dfrac{11-7\sqrt{2}}{-1}

\sf \implies -11+7\sqrt{2}

7 0
2 years ago
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