If we consider the first half mile to be charged at $0.30 per tenth also, that half-mile costs $1.50 and the charges amount to a fixed fee of $2.00 and a variable fee of $0.30 per tenth mile.
After you subtract the $2 tip and the fixed $2 fee from the trip budget amount, you have $11.00 you can spend on mileage charges. At 0.30 per tenth mile, you can travel
... $11.00/$0.30 = 36 2/3 . . . . tenth-miles
The trip is measured in whole tenths, so you can ride ...
... 36 × 1/10 = 3.6 miles
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If you want to see this in the form of an equation, you can let x represent the miles you can travel. Then your budget amount gives rise to the inequality ...
... 3.50 + 0.30((x -.50)/0.10) + 2.00 ≤ 15.00
... 3.50 + 3x -1.50 +2.00 ≤15.00 . . . . . . . eliminate parentheses
... 3x ≤ 11.00 . . . . . . . . . . . . . . . . . . . . . . . . collect terms, subtract 4
... x ≤ 11/3 . . . . . . . . . . . . . . . . . . . . . . . . . . divide by 3
... x ≤ 3.6 . . . . . rounded down to the tenth
The principle SQRT of 100 would be 10 because 10*10 is 100
The first and the second one.
-2*-2=4
Absolute value of -4 is 4
Answer:
(5 , 7)
Step-by-step explanation:
let a = the number of adult tickets
let c = the number of children tickets
then we have to solve the following system
a + c = 12
14.5a + 9c = 135.5
we proceed by Substitution:
c = 12 - a
14.5a + 9c = 135.5
After some calculations we find
a=5 and c=7
11,000 or 10,000 or 11,200 or 11,230
