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Dmitry_Shevchenko [17]
3 years ago
13

What is the area of the figure?

Mathematics
2 answers:
kipiarov [429]3 years ago
5 0
Let’s separate the figure into 2 parts to answer the question easier.
If we seperate he figure into 2 reasonable shapes, we get a rectangle with a width of 8 and a length of 20 and another shape with a width of 4 and a length of 5.

All we need to do to solve this question is to find the areas of both and add them together.
Let’s use the equation wl=a or width*length=area, and insert the known values for the first shape.
8*20=160
Now repeat for the second shape.
4*5=20
Finally, add the two together to get he total area.
160+20=180
The shape has an area of 180 square inches.
Hope this helps!
Nonamiya [84]3 years ago
4 0

Answer:

Step-by-step explanation:

AMSWER is A .180

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circle

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Solution: We have to find the Frequency and Relative frequency of the given data:

Frequency is the number of times a number occurs.

Relative Frequency is the number of times a number occurs divided by the total number of items.

Therefore, the frequency and relative frequency are calculated as below:

Number       Frequency          Relative Frequency

20                       1                     \frac{1}{31} \times 100 =3.2\%

21                        4                    \frac{4}{31} \times 100 =12.9\%

22                       2                    \frac{2}{31} \times 100 =6.5\%

23                       4                    \frac{4}{31} \times 100 =12.9\%

24                       3                    \frac{3}{31} \times 100 =9.7\%

25                       2                    \frac{2}{31} \times 100 =6.5\%

26                       3                    \frac{3}{31} \times 100 =9.7\%

27                       5                    \frac{5}{31} \times 100 =16.1\%

28                       3                    \frac{3}{31} \times 100 =9.7\%

29                       4                    \frac{4}{31} \times 100 =12.9\%

Total                  31

6 0
3 years ago
FIVE STARS AND BRAINLIEST FOR CORRECT ANSWER
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For the given vectors \vec{a}=a_{1}\hat{i}+a_{2}\hat{j} and \vec{b}=b_{1}\hat{i}+b_{2}\hat{j}

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So, \vec{a}.\vec{b} = (4\hat{i}+3\hat{j}). (-4\hat{i}+4\hat{j})

\vec{a}.\vec{b}=(4\times(-4)+3 \times4)

= -16+12

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