9.45 x 10^-5 In standard form
1 answer:
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Answer:
0.7455
Step-by-step explanation:
First, we note that there are C = 220 ways of selecting the defective items.
The probability that the inspector will have to test at least 9 widgets would be 1 minus the probability that the inspector will have to test 8 or less widgets.
This is 1 - P(8 or less widgets have to be checked)
1 -
= 1 - 56/220
= 1 - 0.2545
= 0.7455