Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Answer:
Its A i just took the test
Step-by-step explanation:
A. x=the cost of one lunch. 60.25=5x+3(x-5.25)
b. 60.25=5x+3x-15.75 60.25+15.75=8x-15.75+15.75
76=8x 76/8=8x/8 9.50=x
A lunch is $9.50. If you are not sure, check my answers. Hope this helped.
