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Anna007 [38]
3 years ago
8

Benji, a 12 kg Border terrier, requires daily injections of ampicillin 15% for 3 days. The dose rate is 7.5

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:140

Step-by-step explanation:

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2x-3=-(4x+9) epic bruh moment,i cant seem to get this right someone please answer it for me.
tatyana61 [14]

Answer: x = -1

Step-by-step explanation:

  • 2x-3= - 4x+9
  • 2x+4x = -9 + 3
  • 6x = -9 + 3
  • 6x/6 = -6/6
  • x = -1
8 0
3 years ago
A red light
ANEK [815]

Answer:

Both lights would flash together after every 30 seconds.

Step-by-step explanation:

6 = 2 * 3 and 10 = 2 * 5.

LCM (Least Common Multiple) of 6 and 10 = 2 * 3 * 5 = 30.

Therefore, both lights wold flash together after every 30 seconds.

3 0
3 years ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
Find the greatest common factor of the terms in the following expression: 6ab + 12a
pshichka [43]
6a
So you would write the factored equation as 6a(b+2)
3 0
3 years ago
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The circumference of a circle is 53.38 centimeters what is the area in square centimeters
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What the answer I need today

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