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timofeeve [1]
2 years ago
11

2. The triangles are similar. Show how they are similar and justify your answer.

Mathematics
1 answer:
Yuliya22 [10]2 years ago
3 0

They are similar because they have equal corresponding angles and proportional sides.

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PLEASE HELP 15 POINTS
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=145.
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It is the last option

Step-by-step explanation:

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4 0
3 years ago
What are the solutions of 3x2 + 14x + 16 = 0?
Leya [2.2K]

Answer:

Given the equation: 3x^2+14x+16=0

The general equation of quadratic formula for ax^2+bx+c=0 where a, b and c are constant;

then, the solution for this equation  is given by;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}              ......[1]

From the equation, 3x^2+14x+16=0 we have

a =2, b=14 and c=16

Substitute these values in [1] to solve for x;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-14\pm\sqrt{(14)^2-4(3)(16)}}{2(3)}              

or

x=\frac{-14\pm\sqrt{196-192}}{6} =\frac{-14\pm\sqrt{4}}{6}

Simplify:

x=\frac{-14\pm\sqrt{4}}{6} =\frac{-14\pm 2}{6}

then,

x=\frac{-14+2}{6} =\frac{-12}{6} =-2 and

x=\frac{-14-2}{6} =\frac{-16}{6} =\frac{-8}{3}

Therefore, the solutions for the given equation is; x =-2 and x =-\frac{8}{3}



6 0
3 years ago
Read 2 more answers
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