Answer:
Length of AB = 6 cm
Length of the segment BC = 14 cm
Step-by-step explanation:
Here, B is a point on a segment AC.
AB : BC = 3:7
Length of the segment AC = 20 cm
Now, let the common ratio between the segment is x.
So, the length of AB = 3 x , and Length of BC = 7 x
Now, AB + BC = AC
⇒ 3x + 7x = 20
or, 10 x = 20
or, x = 2
Hence, the length of AB = 3 x = 3 x 2 = 6 cm
and the length of the segment BC = 7x = 7 x 2 = 14 cm
Answer:
Which point would map onto itself after a reflection across the line y = -x? ... What is the pre-image of vertex A' if the image shown on the graph was created by a reflection across the ... A triangle has vertices at R(1, 1), S(-2, -4), and T(-3, -3). ... Which shows the image of quadrilateral ABCD after the transformation R0, 90°? a.
Step-by-step explanation:
Answer:
Option C: 41
Step-by-step explanation:
<ABD+<CBD=90
<ABD=8x+1
<CBD=6x+5
(8x+1)+(6x+5)=90
Combine like terms
(8x+6x)+(1+5)=90
14x+6=90
14x=90-6
14x=84
divide both sides by 14
x=6
Now we plug that value into <DBC = 6x+5
6(6)+5=
36+5
41
Total Area: T.A.=2*Ab+Al
Area of the base: Ab=p*K
Semi-perimeter of the base: p
p=P/2
Perimeter of the base: P=20
p=P/2=20/2→p=10
Ab=p*k=10*K→Ab=10K
Lateral Area of the prism: Al
Al=P*h
Height of the prism: h=6
Al=P*h=20*6→
Al=120
T.A.=2*Ab+Al
T.A.=2*(10K)+120
T.A.=20K+120
T.A.=120+20K
Answer: (120+20K)
From cosine law
c^2 = a^2 + b^2 -2abcos(C)
cos(C) = (a^2 + b^2 - c^2)/2ab
this formula will solve your problem
