3 years ago

Please help its hard btw

Mathematics

1 answer:

Rudiy273 years ago

7 0

Answer:

4213

Step-by-step explanation:

go to the numbers that pop out and do it backwards.

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Simplify:$$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}$$

bagirrra123 [75]

Answer:

$5\sqrt{3}$

Step-by-step explanation:

$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}=?\\\\1)\sqrt{8^2+15^2}=\sqrt{289}=17\\2)\sqrt{9^2+40^2}=\sqrt{1681}=41\\3)2\times17=34\\4)\sqrt{34+41}=5\sqrt{3}$

All Done!

8 0

3 years ago

Read 2 more answers

White raven [17]

8x=6x+20 Btw I figures it out x=10

4 0

3 years ago

The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

musickatia [10]

Answer:

$P(X \geq 1)=1-P(X$

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

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2 years ago

What is the range of range of the relation shown in the table?

seropon [69]

-2Step-by-step explanation:

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2 years ago

100 POINTS!!!!!! HELP

irga5000 [103]

A - 1766! I hope this helps

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3 years ago