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Fiesta28 [93]
4 years ago
8

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and

building B is 35 feet away. Which building is taller and by approximately how many feet? Building A; it is around 16.35 feet taller than building B Building A; it is around 114.48 feet taller than building B Building B; it is around 16.35 feet taller than building A Building B; it is around 114.48 feet taller than building A

Mathematics
1 answer:
grigory [225]4 years ago
3 0

Answer:

The correct option is:

Building B; it is around 16.35 feet taller than building A.

Step-by-step explanation:

Consult the diagram below where the first figure represent building A and second figure represents building B

For building A:

tan θ = Perpendicular / Base

tan 73° = Height of building A / 30

Height of building A = tan73 · 30

Height of building A = 98.13 ft

For building B:

tan θ = Perpendicular / Base

tan 73° = Height of building B / 35

Height of building A = tan73 · 35

Height of building A = 114.48 ft

Building B is taller

Difference in height = height of building B - height of building A

Difference in height = 114.48 - 98.13 = 116.35 feet

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Answer:

45, 60, 75

Step-by-step explanation:

The ratio of the angles are 6:8:10

Multiply by x to get the angle measures

6x, 8x,10x

We know the sum of the angles is 180 for a triangle

6x+8x+10x = 180

Combine like terms

24x = 180

Divide each side by 24

24x/24 = 180/24

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Step-by-step explanation:

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What is the rate of change for the sequence shown below. (1,2) (2,2.5) (3,3) (4,3.5) (5,4)
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Answer:

0.5

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We can see that there is a common difference of d=0.5.

Better still we could use the slope formula:

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