Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and
building B is 35 feet away. Which building is taller and by approximately how many feet? Building A; it is around 16.35 feet taller than building B Building A; it is around 114.48 feet taller than building B Building B; it is around 16.35 feet taller than building A Building B; it is around 114.48 feet taller than building A
1 answer:
Answer:
The correct option is:
Building B; it is around 16.35 feet taller than building A.
Step-by-step explanation:
Consult the diagram below where the first figure represent building A and second figure represents building B
For building A:
tan θ = Perpendicular / Base
tan 73° = Height of building A / 30
Height of building A = tan73 · 30
Height of building A = 98.13 ft
For building B:
tan θ = Perpendicular / Base
tan 73° = Height of building B / 35
Height of building A = tan73 · 35
Height of building A = 114.48 ft
Building B is taller
Difference in height = height of building B - height of building A
Difference in height = 114.48 - 98.13 = 116.35 feet
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Answer:
I think this is a pretty good question of law of indices
Step-by-step explanation:
Given that
a) express n in terms of p and q ,
b) hence if p = 1 and q = 2 find the value of n
Solution to part a)
Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,
now we multiply p with 2 and
multiply q with 3 respectively,
now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base
now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,
hence n is expressed in terms of p and q
Solution to part b)
if p = 1 and q = 2 we plug in these values in the above equation we found for n
n = 2p + 3q
n = 2(1) + 3(2)
n = 2 + 6
n = 7