Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
Answer:
0.3339 = 33.39% probability that both Dave and Mike will show up
Step-by-step explanation:
Probability of independent events:
If A and B are independent events, the probability of both happening at the same time is given by:
In this question:
Event A: Dave shows up.
Event B: Mike shows up.
Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.
This means that 
.
a. What is the probability that both Dave and Mike will show up
0.3339 = 33.39% probability that both Dave and Mike will show up
The correct option is the second one y<=1/2x+3
Answer: 16, 10, 64
Step-by-step explanation:
64/4=16, so the 3rd number is 4x the first.
16-6=10. 6 less than the first number.
16+10+64=90.
