1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ale4655 [162]
3 years ago
15

A small spaceship whose mass is 1300 kg (including an astronaut) is drifting in outer space with negligible gravitational forces

acting on it. If the astronaut turns on a 11 kW laser beam, what speed will the ship attain in 4.0 days because of the momentum carried away by the beam?
Physics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

Explanation:

Relation between energy and momentum is as follows .

E = h c / λ

E / c = h / λ

h /λ = momentum of a photon

momentum of a photon  = E /c

= 11 x 10³ / 3 x 10⁸

= 3.67 x 10⁻⁵

In 4 days no of photon

= 4 x 24 x 60 x 60 = 345600 .

momentum of photon released

3.67 x 10⁻⁵  x 345600 .

= 12.68 kg m/s

This momentum will be imparted to spaceship .

12.68 = mv

12 .68 = 1300 x v

v = .00975 m /s

= 9.75 mm /s

You might be interested in
The laws of reflection holds for__
RSB [31]

Answer:

c)both

Explanation:

The laws of reflection hold true for all the reflecting surfaces either spherical or plane. Therefore, the plane mirror, concave mirror and the convex mirror all will follow the laws of reflection.

5 0
3 years ago
Read 2 more answers
A volleyball is knocked from rest to a velocity of 22 m/s over a time of 0.2
notsponge [240]

Answer:

\boxed {\boxed {\sf 55 \ Newtons}}

Explanation:

We are asked to find the force applied to the volleyball. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F=ma

We are given the mass, but we must calculate the acceleration.

1. Acceleration

Acceleration is the rate of change of velocity with respect to change. It is the change in velocity over the time.

a= \frac{v_f-v_i}{t}

The volleyball starts at rest or 0 meters per second and reaches a velocity of 22 meters per second in 0.2 seconds.

  • v_f= 22 m/s
  • v_i= 0 m/s
  • t= 0.2 s

Substitute the values into the formula.

a= \frac{ 22 \ m/s - 0 \ m/s}{0.2 \ s}

Solve the numerator.

a= \frac{22 \ m/s}{0.2 \ s}

Divide.

a= 110 \ m/s^2

2. Force

Now we know the mass and acceleration, so we can calculate the force.

F=ma

The mass is 0.5 kilograms and the acceleration is 110 meters per second squared.

  • m= 0.5 kg
  • a=110 m/s²

Substitute the values into the formula.

F= 0.5 \ kg * 110 \ m/s^2

Multiply.

F= 55 kg*m/s^2

1 kilogram meter per second squared is equal to 1 Newton, so our answer of 55 kg*m/s² is equal to 55 Newtons.

F= 55 \ N

<u>55 Newtons</u> of force are applied to the volleyball.

3 0
3 years ago
The greatest ocean depths on the earth are found in the marianas trench near the philippines. calculate the pressure due to the
tensa zangetsu [6.8K]
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:

P = ρgh

This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:

P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
6 0
3 years ago
A car accelerates at a rate of 4.00 m/swest for 5.0 seconds. What is the car's change in
andre [41]

Answer:

20 m/s

Explanation:

Acceleration = Change in velocity/ time

4 = Change in Velocity/ 5

Change in velocity = 20 m/s

3 0
3 years ago
The ____ is a wedge-shaped thickening in the middle layer of the eyeball that controls the shape of the lens.
Yanka [14]

The ciliary body is a wedge-shaped thickening in the middle layer of the eyeball that controls the shape of the lens.

The ciliary body is a section of the middle layer of the eye's wall. It is located behind the iris.  It includes a ring-shaped muscle that modifies the curvature of the lens when the eye focuses.

Additionally, it creates the transparent liquid that fills the area between the iris and the cornea. Aqueous humor is the name of this fluid in the eye.

It also contains the ciliary muscle, which modifies the lens' shape when your eyes focus on a close object.

The anterior pars plicata and the posterior pars plana are two parts of ciliary body. The anterior vitreous comes into contact with the pars plana, which creates a smooth surface. The ciliary processes, which are 70–80 radiating ridges, are produced by the pars plicata.

To learn more about the molar mass please click on the link brainly.com/question/14042796

#SPJ4

8 0
2 years ago
Other questions:
  • Why does Doug need to adjust his workouts when they seem too easy?
    11·1 answer
  • A machine that has no friction to overcome is called
    10·2 answers
  • Since the moon has less mass then the earth what happens to objects on the moon
    12·1 answer
  • Heptane is always composed of 84.0% carbon and 16.0% hydrogen. This illustrates the law of multiple proportions. conservation of
    6·1 answer
  • Our eyes can detect light only within a range of ____________ called visible light. frequencies speeds mediums periods
    8·1 answer
  • When an electron de-excites from the third quantum level to the second, and then to the ground state, two photons are emitted. T
    13·1 answer
  • An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?
    8·1 answer
  • !!! HELP PLEASE !!!
    15·1 answer
  • What acceleration is produced on a mass of 200g, when a force of 10N is exerted on it?​
    13·1 answer
  • NEED HELP NOW I WILL BRAINLIEST
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!