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Rashid [163]
4 years ago
11

Despite a very strong wind, a tennis player manages to hit a tennis ball with her racquet so that the ball passes over the net a

nd lands in her opponents court. Consider the following forces: 1 - A downward force of gravity. 2 - A force by the "hit". 3 - A force exerted by the air. Which of the above forces is (are) acting on the tennis ball after it has left contact with the racquet and before it touches the ground?
Physics
1 answer:
kobusy [5.1K]4 years ago
5 0

Answer:

The downward force of gravity and the force exerted by the air.

Explanation:

Gravity, in a Newtonian Framework, acts at distance, so, the ball doesn't has to be connected to Earth to feel its gravitational pull (as we know by experience).

The racket only can exert a force in the ball when is touching it, so, once the ball has left the contact with the racket, there is no force by the "hit".

The air is always touching the ball on the atmosphere (even when physicist pretend that is not). So, there is drag from the wind, and a buoyant force  exerted by the air over the ball at every time.

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Objects with masses of 130 kg and a 430 kg are separated by 0.300 m.(a) Find the net gravitational force exerted by these object
fredd [130]

Answer

given,

mass of object

m₁ = 130 Kg

m₂ = 430 Kg

distance between them = 0.3 m

a) net force when 35 kg is place in between them

   F = \dfrac{GMm}{R^2}

now,

   F = - \dfrac{6.67 \times 10^{-11}\times 130 \times 30}{0.15^2} +\dfrac{6.67 \times 10^{-11}\times 430 \times 30}{0.15^2}

   F = 3.12 \times 10^{-5}\ N

   Direction of force will be toward the mass of 430 Kg

b) position where force will be zero

 F =-\dfrac{6.67 \times 10^{-11}\times 130 \times 30}{(0.3-x)^2} +\dfrac{6.67 \times 10^{-11}\times 430 \times 30}{x^2} = 0

 -\dfrac{130}{(0.3-x)^2} +\dfrac{430}{x^2} = 0

 x^2- 0.6 x + 0.09=\dfrac{130}{430}x^2

 0.7 x^2- 0.6 x + 0.09 =0

solving the above equation

  x = 0.1936 m

the distance of third mass will be at x = 0.1936 m from 430 Kg mass.

7 0
3 years ago
60 POINT!!!!!!
Paladinen [302]

Answer:

h and I have been working on the sea for the last few days

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How to convert 45.77 cubic inches to cubic centimeters
Paha777 [63]
45✖️77 and then you will get your answer
6 0
3 years ago
What type of tool seems to be the mist accurate for measuring liquids?
Anit [1.1K]

Volumetric flasks are most accurate

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3 years ago
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a teacher drives from school to the mall. then she goes to the doctors office for a physical examination. what is the magnitude
Amanda [17]

The magnitude of the teachers displacement is the difference between

the location of the school and the location of the doctors office

The reason behind the above expression are explained as follows

The known locations of the teacher;

Initial location; The school

Second location; The mall

The eventual location; The doctors office

The required information;

The magnitude of the teachers displacement

The method of obtaining the displacement of the teacher;

Qualitatively, the displacement of the teacher can be obtained by applying the definition of displacement as follows;

The definition of displacement is an object's change in position, given by the difference between its start and finish locations

According to the definition of displacement, therefore, the magnitude of

the teachers displacement is the distance between the school and the

doctors office which is given by the difference between the coordinates of

the location of the school and the location of the doctors office

The magnitude of the displacement of the teacher = The coordinate of the location of the doctors office - The coordinate of the location of the school

Learn more about displacement here;

brainly.com/question/17587058

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