Answer:
Java program is explained below
Explanation:
import java.util.HashSet;
import java.util.Map;
import java.util.TreeMap;
public class TruckRace1 {
public static HashSet<String> getPIDs (Map<String,String>nameToPID ){
HashSet<String> pidSet = new HashSet<>();
for(String ids: nameToPID.values()){
pidSet.add(ids);
}
return pidSet;
}
public static void main(String[] args) {
Map<String,String> pids = new TreeMap<>();
pids.put("John","123");
pids.put("Jason","124");
pids.put("Peter","125");
pids.put("Alice","126");
pids.put("Peny","129");
HashSet<String> ids = getPIDs(pids);
for(String id:ids){
System.out.println(id);
}
}
}
Answer:
Code is provided in the attachment form
Explanation:
Vector Multiplication code:
Vector_multiplication.c file contains C code.
See attachment no 1 attached below
Classification of Algorithm: For creating elements in vector c of size n, number of scalar multiplications is equal to n. The size of original two vectors scales directly with the number of operations. Hence, it is classified as O(n).
<u>Answer:</u>
The correct answer option is D. set the switch to the highest range and then move it to a range that gives the most accurate reading.
<u>Explanation:</u>
When measuring an unknown voltage with an analog VOM, one should set the meter to the highest range and then move it to a range that gives the most accurate reading.
The reason being that the analog meters indicate the measurement of voltage by moving a needle across a physical card by printing numbers on it.
So in case the voltage is nearly 100 times the full range to which the meter is set, then its needle will try move to a position which will be 100 times the highest number on the meter.
A place to watch daisy Taylor vids
I guess the correct answer is the Enter key
Οn cοmputеr kеybοards, thе еntеr kеy in mοst casеs causеs a cοmmand linе, windοw fοrm, οr dialοg bοx tο οpеratе its dеfault functiοn. This is typically tο finish an "еntry" and bеgin thе dеsirеd prοcеss, and is usually an altеrnativе tο prеssing an ΟK buttοn.
