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xxMikexx [17]
3 years ago
15

How does the concept of polarity relate to bond formation and molecular shape?

Chemistry
1 answer:
Ket [755]3 years ago
5 0

Answer: heyyyooo

The bond polarity for each bond in a BH3 molecule is polar, due to the difference in electronegativities of the B and H atom. The molecular shape is trigonal planar, and the molecule is non-polar - because due to the symmetry of the molecule, the polarities cancel out.

Explanation:

hope this helps!

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hich of these statements is supported by the results of Thomson’s experiment? Check all of the boxes that apply.
snow_tiger [21]

Cathode rays are made up of negatively charged particles.

Atoms contain negatively charged particles.

Explanation:

The experiment carried out by J.J Thomson provided evidence to support that fact that atoms contains negatively charged particles and that cathode rays are negatively charged.

J.J Thomson performed experiments using a gas discharge tube.

  • Through his experiment, he discovered cathode rays.
  • From his observation, he noticed that they were attracted to the another so they must be negatively charged.
  • He called the rays cathode rays.
  • Today, they are known as electrons.
  • Thomson's experiment discarded the widely held believed that atoms are indivisible.

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Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p
UNO [17]

Answer : The equilibrium constant K_c for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of Br_2.

\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}

\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M

Now we have to calculate the dissociated concentration of Br_2.

The balanced equilibrium reaction is,

                              Br_2(g)\rightleftharpoons 2Br(aq)

Initial conc.         1.731 M      0

At eqm. conc.      (1.731-x)    (2x) M

As we are given,

The percent of dissociation of Br_2 = \alpha = 1.2 %

So, the dissociate concentration of Br_2 = C\alpha=1.731M\times \frac{1.2}{100}=0.2077M

The value of x = 0.2077 M

Now we have to calculate the concentration of Br_2\text{ and }Br at equilibrium.

Concentration of Br_2 = 1.731 - x  = 1.731 - 0.2077 = 1.5233 M

Concentration of Br = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

K_c=\frac{[Br]^2}{[Br_2]}

Now put all the values in this expression, we get :

K_c=\frac{(0.4154)^2}{1.5233}=0.1133

Therefore, the equilibrium constant K_c for the reaction is, 0.1133

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In what type of reaction or process does heat flow into the system?
Ne4ueva [31]

Answer:

Endothermic

Explanation:

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