1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkinab [10]
3 years ago
8

Anyone need sugar daddy​

Chemistry
2 answers:
poizon [28]3 years ago
6 0

Answer:

daddy cute ;)

Explanation:

Ber [7]3 years ago
4 0

Answer:

EEEE

Explanation:EEE

You might be interested in
A gas sample has volume 3.00 dm3 at 101
gavmur [86]

Answer:

V₂ = 21.3 dm³

Explanation:

Given data:

Initial volume of gas = 3.00 dm³

Initial pressure = 101 Kpa

Final pressure = 14.2 Kpa

Final volume = ?

Solution;

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 Kpa × 3.00 dm³ = 14.2 Kpa × V₂

V₂ = 303 Kpa. dm³/  14.2 Kpa

V₂ = 21.3 dm³

Explanation:

3 0
3 years ago
A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?
Doss [256]

Answer:

d = 43.5 g/cm³

Explanation:

Given data:

Mass of magnesium cube = 217.501 g

Volume of magnesium cube = 5.00 cm³

Density of magnesium cube = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

d = 217.501 g/ 5.00 cm³

d = 43.5 g/cm³

8 0
3 years ago
Kinetic energy differs from chemical energy in that
Sliva [168]
Chemical energy is the answer to your question
6 0
3 years ago
An astronomer studying planets outside our solar system has analyzed the atmospheres of four planets. Which of these planets’ at
Nata [24]

Answer: Planet A: 76% Nitrogen, 23% Oxygen, 1% Other

Explanation: Hope this helps!

3 0
3 years ago
What volume of 0.500 m h2so4 is needed to react completely with 20.0 ml of 0.400 m lioh?
ExtremeBDS [4]
The balanced chemical equation for the above reaction is as follows;
2LiOH + H₂SO₄ ---> Li₂SO₄ + 2H₂O
stoichiometry of base to acid is 2:1
Number of OH⁻ moles reacted = number of H⁺ moles reacted at neutralisation
Number of LiOH moles reacted = 0.400 M / 1000 mL/L x 20.0 mL = 0.008 mol 
number of H₂SO₄ moles reacted - 0.008 mol /2 = 0.004 mol 
Number of H₂SO₄ moles in 1 L - 0.500 M
This means that 0.500 mol  in 1 L solution 
Therefore 0.004 mol in - 1/0.500 x 0.004 = 0.008 L 
therefore volume of acid required = 8 mL 
4 0
3 years ago
Other questions:
  • If horizontal layers of sedimentary rock have a vertical fault running through them, how might a geologist use relative dating t
    10·2 answers
  • In a laboratory experiment, john uses a message to seperate soil particles from water . Which technique separation which techniq
    11·1 answer
  • Based on the results of this lab, write a short paragraph that summarizes how to distinguish physical changes from chemical chan
    9·2 answers
  • What is atom economy?
    7·1 answer
  • Predicting nuclear stability is important when determining whether or not a nuclear reaction can take place spontaneously.Use th
    12·1 answer
  • QUICK WILL MARK BRAINIEST!!!! The general formula for an acid is (__n ___) where _____ stands for hydrogen, n stands for the ___
    5·1 answer
  • A cylinder contains 3.1 L of oxygen at 300 K and 2.7 atm. The gas is heated, causing a piston in the cylinder to move outward. T
    7·1 answer
  • What is magma called once<br> leaves a volcano?
    12·1 answer
  • The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the
    14·1 answer
  • Describe the concentration of hydronium ions and hydroxide ions when a base is added slowly to a white vinegar solution. The pH
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!