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3 years ago

How to open tylenol extra strength bottle?

Chemistry

2 answers:

jek_recluse [69]3 years ago

6 0

Answer:

Explanation: We all know that it is a little bit difficult task to open a tylenol extra strength bottle but by following the below written guidelines, one can find an easy way to open it.

Match up the arrows first

Then get a metal spoon

Put the edge of the spoon directly under the arrow pointing down

Push the spoon up

The cap should pop off

Now one can easily open the extra strength bottle.

sashaice [31]3 years ago

5 0

With the palm of your hand, push the lid down, as you apply this pressure on the lid twist slightly. Once you are able to get movement, use your fingers to keep twisting until the lid is completely off. :)

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Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc

jeka94

Answer:

$T_f$ = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

$T_i$ = 21.5°C

$C_{calorimeter}$ = 6.15 kJ/°C

$T_f$ = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate × $\frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}$

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

= 0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter = $C_{calorimeter}$ $(T_f-T_i} )$

21.84 kJ =6.15 kJ/°C $* (T_f-21,5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f)$ - 132.225 kJ

21.84 KJ + 132.225 kJ = $(6.15 kJ/^0C * T_f)$

154.065 kJ = $(6.15 kJ/^0C * T_f)$

$T_f$ = $\frac{154.065kJ}{6.15kJ/^0C}$

$T_f$ =25.05°C

4 0

4 years ago

Wskaż substancję, która ma największą zawartość procentową węgla w cząsteczce:

MrRa [10]

Answer: C2H4

Explanation:

The percentage composition of ethanol ( C2H5OH ) consist of 52.2% Carbon, Hydrogen of 13.0 and 34.8% of Oxygen.

The percentage composition of ethane gas (C2H6) consist of 80.0% carbon and 20.0% hydrogen.

The composition of Ethylene Glycols i.e C2H4(OH)2 is Carbon of 39.7%, 9.7% hydrogen and 51.6% oxygen.

The percent composition of c2h4 is 86% carbon, and 14% hydrogen.

From the information given, the substance with the highest percentage of carbon is C2H4

7 0

4 years ago

1. According to the fossil record, the first LAND plants were most likely pine trees. moss and ferns. flowering plants. 2. Scien

Lynna [10]

Answer:

It is true that earth was once covered with oceans and little dry land.

Explanation:

Over the course of around four billion years, the Earth's oceans have lost about a quarter of their original mass. Today the atmosphere is rich in oxygen, which reacts with both hydrogen and deuterium to recreate water, which falls back to the Earth's surface. So the vast bulk of the water on Earth is held in a closed system that prevents the planet from gradually drying out. According to the researchers, the continents emerged relatively suddenly from an ocean that covered 95 percent of the Earth's surface. The appearance of large masses of dry land would have caused more extreme weather, changes in ocean currents and the emergence of proper seasons. In turn, these environmental changes may have led to rise in atmospheric oxygen that enabled the explosion of new life forms around 500 million years ago.

7 0

3 years ago

Read 2 more answers

Why is BCl3 a non-polar compound?

Firdavs [7]

Answer:

BCI3 is a non polar compound because there is no neutral in it

4 0

3 years ago

Why is it important to note the temperature when determining the density of a substance?

Andru [333]

It is important to take note of th temperature in determining the density of a substance because this will set as a basis and will likely be a variable in the experiment because this will also contribute on the effects of the experiment and a basis of how the experiment has turned to be that way.

7 0

3 years ago