Answer:
-431.5 J/g
Explanation:
Mass of solution = Mass of solute + mass of solvent
Solute is KOH while solvent is water.
Mass of KOH = 16.9 g
Mass of water = 90.8 g
Mass of solution = 16.9 + 90.8
= 107.7 g
Change in temperature (Δt) = 34.27 - 18.5
= 16.2 °C
Heat required to raise the temperature of water is released by dissolving KOH.
Therefore,
Heat released by KOH = m × s× Δt
= 107.7 × 4.18 × 16.2
= 7293 J
Heat released by per g KOH = 7293 J/16.9 g
= 431.5 J/g
As heat is released therefore, enthalpy change would be negative.
Enthalpy change of KOH = -431.5 J/g
THE COMPLETE QUESTION IS:
Determine whether each cation is acidic or pH-neutral. For those cations that are acidic, write an equation that shows how the cation acts as an acid . a. NH+4 b. Na+ c. Co3+ d. CH2NH+3
Answer:
<em>a. Acidic</em>
<em>b. neutral</em>
<em>c. Acidic</em>
<em>d. Acidic</em>
Explanation:
a. NH4+ + H2O <==> NH3 + H3O+ (NH4+ is a conjugate acid of a weak base. Therefore it is acidic)
b. Neutral. Na+ is a cation of a strong base. Therefore it's pH is neutral.
c. Co(H2O)6³+ + H2O <==>CoH2O5(OH)²+ + H3O+
(Therefore Co+ is a weak acid since hydronium ion is formed.)
d. CH2NH3+ is a conjugate acid of a weak base. Therefore it is acidic.
Answer:
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