3 years ago

Of the 20 students on a field trip, 11 brought lunch from home. What percent of students brought lunch?? From home? *

1 answer:

meriva3 years ago

8 0

It’s going to be 55 percent

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jek_recluse [69]

Answer:3240<50s*81=4050

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3 years ago

DerKrebs [107]

$4[2.5+3(20+7)]=4[2.5+3 \cdot 27]=4[2.5+81]=4 \cdot 83.5=334$

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4 years ago

Drupady [299]

Answer:

Correct choice is B

Step-by-step explanation:

Let x% be your final test score, then the average of all test scores is

$\dfrac{96+77+74+x}{4}.$

Since you must have an average between 80% and 89%, then

$80\le \dfrac{96+77+74+x}{4}\le 89,\\ \\320\le 247+x\le 356,\\ \\73\le x\le 109.$

X is measured in percent, then the greatest value of x can be 100%. You get that

$73\%\le x\le 100%.$

4 0

4 years ago

vlabodo [156]

Answer:

6 edges

I hope it helps

8 0

2 years ago

11Alexandr11 [23.1K]

Now it would be
-2.3+(-5.9)

now just add those two together
and u get -8.2
So the answer is A

7 0

3 years ago