1) Calculate the number of moles in 1.15 liter of 0.100 M HNO3 solution.
M = n / V => n = M*V = 0.100M * 1.15 l = 0.115 moles
2) Calculate the mass of 0.115 moles of HNO3
mass = number of moles * molar mass
molar mass of HNO3 = 1.00 g/mol + 14.0 g/mol + 3*16.0g/mol = 63.0 g/mol
mass = 0.115 mol * 63.0g/mol = 7.245 g
3) Calculate the mass of 70.3% HNO3 solution that contains 7.245 grams of HNO3
% = (mass of solute / mass of solution) * 100
=> mass of solution = mass of solute * 100 / % = 7.245 g * 100 / 70.3%
mass of soltuion = 10.3 g.
4) Convert 10.3 grams of HNO3 solution into volume, using density, D
D =mass / Volume => Volume = mass / D
=. Volume = 10.3 g / 1.41 g/cm^3 = 7.30 cm^3
Answer: 7.30 cm^3
Answer:
half life=0.693/rate constant =188.3
Answer:
it is formed by covalent bonds. the oxygen atom shares one elctron with each chlorine atom, forming single covalent bonds ( cl — o — cl )
I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y,
for the following reason:
If you look at the combining masses of X and Y in
each of the two compounds,
The first compound contains 0.25g of X combined with
0.75g of Y
so the ratio (by mass) of X to Y = 1 : 3
The second compound contains 0.33 g of X combined with
0.67 g of Y
so the ratio (by mass) of X to Y = 1 : 2
Now, you suppose to prepare each of these two
compounds, starting with the same fixed mass of element Y ( I will choose 12g
of Y for an easy calculation!)
The first compound will then contain 4g of X and 12g
of Y
The second compound will then contain 6g of X and
12g of Y
<span>The ratio which combined
the masses of X and the fixed mass (12g) of Y
= 4 : 6
<span>or 2 : 3 </span>
So, the ratio of MOLES of X which combined with the
fixed amount of Y in the two compounds is also = 2 : 3 </span>
The two compounds given with the plausible formula must therefore contain
the same ratio.