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kow [346]
2 years ago
9

How do you calculate the volume of a cube? A. with a graduated cylindar in mL? B. with a triple beam balance in g? C. with a bea

ker in mL? D. with a ruler in cm3?
Chemistry
1 answer:
Nuetrik [128]2 years ago
5 0

Answer:

B

Explanation:

triple beam balance

sorry if i am wrong! can be brainliest?

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2 years ago
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A molecular orbital is a region of space in a covalent species where electrons are likely to be found. The combination of two at
lara [203]

Answer:

bonding molecular orbital is lower in energy

antibonding molecular orbital is higher in energy

Explanation:

Electrons in bonding molecular orbitals help to hold the positively charged nuclei together, and they are always lower in energy than the original atomic orbitals.

Electrons in antibonding molecular orbitals are primarily located outside the internuclear region, leading to increased repulsions between the positively charged nuclei. They are always higher in energy than the parent atomic orbitals.

5 0
2 years ago
What is the volume of the sphere? Round your answer<br> to the nearest tenth.<br> cm
myrzilka [38]

Answer:

volume

v = 4/3π r^3

Explanation:

it isn't specific enough but that is the equation of how to get any volume

volume equals four thirds times pi times radios to the power of three

4 0
3 years ago
10) an object has mass of 50g 500mg and 0.1g. express the total mass of the object in grams
Pavel [41]
500 mg in g :

1 g ----------- 1000 mg
? -------------- 500 mg

500 x 1 / 1000 => 0.5 g

total mass:

50 g + 0.5 g + 0.1 g => 50.6 g

hope this helps!
8 0
3 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
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