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3 years ago

Please help with question 4 and 5 please!!

Chemistry

1 answer:

ratelena [41]3 years ago

8 0

Question four is : Gaseous state

Question five is : A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.

Hope this helps!

Have a great day!

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Help asap ill give branilsit

stiks02 [169]

A prokaryotic cell is a cell without a nucleus (there's more to it, though).

Let's start from the bottom.

Strawberry plant: Plant cells are eukaryotic (cells have nucleus).
Hippopotamus: Animal cells are eukaryotic (cells have nucleus).
Paramecium: That's an animal, and animal cells are eukaryotic (cells have nucleus).
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Your answer is bacterium.

Have an awesome day! :)

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3 years ago

A man carrying a torch walks though a jungle on a very dark night. Suddenly, he sees two eyes looking down from a tree that seem

Brut [27]

D) The eyes in the tree are reflecting light from the torch into the man's eyes.

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3 years ago

What electron could have quantum numbers n = 4, l = 2, ml = -2, ms = -?

brilliants [131]

The answer is ms= -1/2

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3 years ago

The time necessary for the decay of one- half sample of a radioactive substance is a _____. mass defect daughter half life nucli

Mazyrski [523]

Answer: half life

Explanation: Radioactive decay follows first order kinetics and the time required for the decay of a radioactive material is calculated as follows:

$t=\frac{2.303}{k}\hspace{1mm}log\frac{x}{a}$

t= time required

k= disintegration constant

x= amount of substance left after time t

a= initial amount of substance

when one half of the sample is decayed, one half of the sample remains and t can be represented as $t_{1/2}$

at $t= t_{1/2}$ , $x=\frac{a}{2}$

$t_{1/2}=\frac{2.303}{k}\hspace{1mm}log\frac{a/2}{a}$

$t_{1/2}=\frac{0.693}{k}$

3 0

3 years ago

Read 2 more answers

20 N force moving a box to 30 meters distance. How much work id done? if it takes 10 sec to do this work, how much power is used

dalvyx [7]

Answer:

Work done = 600 J

Power used = 60 W

Explanation:

Given:

Force acting on the box is, $F=20\ N$

Displacement of the box is, $S=30\ m$

Time taken for the work, $t=10\ s$

Now, we know that, work is said to be done by a force only when there is displacement caused by the force in its direction.

Here, the force acting on the box causes a displacement of 30 m in its direction. So, work done is equal to the product of force and displacement caused.

Therefore, work done on the box is given as:

$Work=Force\times Displacement\\Work=F\times S\\Work=(20\ N)\times (30\ m)\\Work=600\ J$

Therefore, the work done is 600 J.

Now, we know that, power is given as work done per unit time.

So, power used is given as:

$Power=\frac{Work}{Time}\\\\Power=\frac{600\ J}{10\ s}\\\\Power=60\ W$

Therefore, the power used is 60 W.

5 0

3 years ago