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omeli [17]
3 years ago
8

As the atomic numbers of the elements in column IIA increase, the size of the atoms generally

Chemistry
2 answers:
joja [24]3 years ago
7 0

Answer:

Increase

Explanation:

Gennadij [26K]3 years ago
7 0

<u>Answer:</u> The size of the atoms increases as the atomic number of the elements in Group II-A increases.

<u>Explanation:</u>

Atomic radius of an atom is defined as the total distance from the nucleus to the outermost shell of the atom.

On moving from top to bottom, an extra shell around the nucleus is added and the outermost shell gets far away from the nucleus and hence, the distance between the nucleus and outermost shell increases. Thus, increasing the atomic radii of the atom on moving from top to bottom.

We are given:

Atoms that are present in Group II-A are Beryllium (Z = 4), Magnesium (Z = 12), Calcium (Z = 20), Strontium (Z = 38), Barium (Z = 56) and Radium (Z = 88)

As, the atomic number increases on moving down the group, so does the atomic radius of the atoms in the group.

Hence, the size of the atoms increases as the atomic number of the elements in Group II-A increases.

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MArishka [77]

Answer:

Mutualism

Explanation:

4 0
3 years ago
Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. C
Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

6 0
3 years ago
A 2.5 L container is filled with propane. The ambient temperature is 25°C and the
madam [21]

Answer:

The pressure inside the container will be 3.3 atmospheres

Explanation:

The relationship between the temperature and pressure of a gas occupying a fixed volume is given by Gay-Lussac's law which states that the pressure of a given amount of gas is directly proportional to its temperature on the kelvin scale when the volume is kept constant.

Mathematically, it expressed as: P₁/T₁ = P₂/T₂

where P₁ is initial pressure, T₁ is initial temperature, P₂ is final pressure, T₂ is final temperature.

The above expression shows that the ratio of the pressure and temperature is always constant.

In the given question, the gas in the can attains the temperature of its environment.

P₁ = 3 atm,

T₁ = 25 °C = (273.15 + 25) K = 298.15 K,

P₂ = ?

T₂ = (55 °C = 273.15 + 55) K = 328.15 K

Substituting the values in the equation

3/298.15 = P₂/328.15

P₂ = 3 × 328.15/298.15

P₂ = 3.3 atm

Therefore, the pressure inside the container will be 3.3 atmospheres

7 0
3 years ago
What is the mass of 5.2 moles of Fe?
sashaice [31]

Answer:

279.225g

Explanation:

7 0
3 years ago
g The reaction C(s) + CO2(g) → 2CO(g) is spontaneous only at temperatures in excess of 1100 K. We can conclude that a. ΔG° is ne
mel-nik [20]

Answer:

c. ΔH° is positive and ΔS° is positive.

Explanation:

Hello,

In this case, as the Gibbs free energy for a reaction is defined in terms of the change in the enthalpy and entropy as shown below:

\Delta G=\Delta H-T\Delta S

Thus, as the reaction becomes spontaneous (ΔG°<0) at temperatures above 1100K (high temperatures), it necessary that c. ΔH° is positive and ΔS° is positive as the entropy will drive the spontaneousness as it becomes smaller than TΔS°.

Best regards.

7 0
3 years ago
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