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omeli [17]
3 years ago
8

As the atomic numbers of the elements in column IIA increase, the size of the atoms generally

Chemistry
2 answers:
joja [24]3 years ago
7 0

Answer:

Increase

Explanation:

Gennadij [26K]3 years ago
7 0

<u>Answer:</u> The size of the atoms increases as the atomic number of the elements in Group II-A increases.

<u>Explanation:</u>

Atomic radius of an atom is defined as the total distance from the nucleus to the outermost shell of the atom.

On moving from top to bottom, an extra shell around the nucleus is added and the outermost shell gets far away from the nucleus and hence, the distance between the nucleus and outermost shell increases. Thus, increasing the atomic radii of the atom on moving from top to bottom.

We are given:

Atoms that are present in Group II-A are Beryllium (Z = 4), Magnesium (Z = 12), Calcium (Z = 20), Strontium (Z = 38), Barium (Z = 56) and Radium (Z = 88)

As, the atomic number increases on moving down the group, so does the atomic radius of the atoms in the group.

Hence, the size of the atoms increases as the atomic number of the elements in Group II-A increases.

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A. Heat because it does not take up space.

3 0
3 years ago
Lana is studying a chemical reaction in which the reactants propane (c3h8) and oxygen gas (o2) react to yield the products carbo
makvit [3.9K]
In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.

Equation:

                          C₃H₁₀ ⁺ 5 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  3 CO₂ ⁺ 4 H₂O

Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.

As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).

Result:

                      ( C₃H₁₀ ⁺ 5 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  3 CO₂ ⁺ 4 H₂O ) ₓ 2

                        2 C₃H₁₀ ⁺ 10 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  6 CO₂ ⁺ 8 H₂O

So, 6 molecules of carbon dioxide and 8 molecules of water are produced.
8 0
3 years ago
A syringe with 32.0 mL contains gas at 649.0 mmHg. The plunger is pushed in and now the volume is 19.5 mL. What is the new press
Natasha2012 [34]

Answer:

1.40 atm

Explanation:

P1V1 = P2V2

P2= P1* V1/V2

P1=649.0mmHg

V1= 32.0mL

V2= 19.5mL

P2=649.0mmHg*32.0ml/19.5ml=

1065.03mmHg

To get mmHg to atm. The formula is 1atm/760mmHg

Use the answer you got in mmHg to convert into (atm), If you were asked

1065.03mmHg*(1atm/760mmHg)= 1.40atm

6 0
3 years ago
If i change it by looking at it what type of change is it ?
Lena [83]

Answer:

the answer to this is non impact

6 0
3 years ago
The radius of a potassium atom is 231 pm. how many potassium atoms would have to be laid side by side to span a distance of 2.86
Readme [11.4K]

Answer:

6.1905\times 10^{6} of potassium atoms are needed.

Explanation:

Radius of the potassium atom,r = 231 pm =2.31\times 10^{-7} mm

1 pm = 10^{-9} mm

Diameter of the potassium atom = d

d=2r=2\times 2.31\times 10^{-7} mm=4.62\times 10^{-7} mm

let the number of potassium atom laid side by side to span a distance of 2.86 mm be x

x\times d=2.86 mm

x\times 4.62\times 10^{-7} mm=2.86 mm

x=\frac{2.86 mm}{4.62\times 10^{-7} mm}=6.1905\times 10^{6}

6.1905\times 10^{6} of potassium atoms would have to be laid side by side to span a distance of 2.86 mm.

4 0
3 years ago
Read 2 more answers
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