The expression for the distance the car travels after t seconds is d = 200t + 50t²
<h3>Equation of motion </h3>
From the question, we are to write an expression for the distance the car travels after t seconds
From the given information,
The equation for the motion of an object with constant acceleration is
d = vt + 0.5at²
For the race car,
v = 200 ft/s
a = 100 ft/s²
Putting the parameters into the equation, we get
d = 200t + 0.5(100)t²
d = 200t + 0.5 ×100)t²
d = 200t + 50t²
Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²
Learn more on Equations of motion here: brainly.com/question/20910641
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Hi there!
Since the triangle is equilateral, all of its sides are congruent. This means that to solve, we can set the two given equations equal to each other.
2(x - 8) = 1/2x + 8
2x - 16 = 1/2x + 8
1.5x - 16 = 8
1.5x = 24
x = 16
Now that we know what x is, we can plug that in for x in the equation for ZY.
2(16 - 8) = ZY
ZY = 2(8)
ZY = 16 units
And here is the work to show that XZ is also 16.
1/2(16) + 8 = XZ
XZ = 8 + 8
XZ = 16
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:1
Step-by-step explanation:the gap is one
Which of the following expression is equal to the following expression:
X + 4x / X^2 - 2x
= 5/X-2
4 thousands = 4000
7 hundreds = 700
16 tens = 160
9 ones = 9
Then you add them all together:
4000 + 700 + 160 + 9
Your answer is 4869.
