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2 years ago

Which pair shows equivalent expressions?

Mathematics

1 answer:

viva [34]2 years ago

3 0

Answer:

Step-by-step explanation:I think

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Can you please help me?<br><br><br> 5/2 times 3/2

e-lub [12.9K]

3.75 (as a decimal) or 3 3/4 (fraction)

6 0

3 years ago

Read 2 more answers

You need to find the distance across a river, so you make a triangle. BC is 661 feet, m∠B=103.2° and m∠C=14.4°. Find AB.

kati45 [8]

Answer:

AB = 185.77 feet

Step-by-step explanation:

From the figure attached, in ΔABC,

m∠B = 103.2°, m∠C = 14.4° and side BC = 661 feet

We have to find the measure of side AB.

Since ∠A + ∠B + ∠C = 180°

∠A + 103.2 + 14.4 = 180

∠A + 117.6 = 180

∠A = 180 - 117.6

= 62.4°

By applying sine rule in the given triangle ABC

$\frac{AB}{sinC}=\frac{BC}{sinA}$

$\frac{AB}{sin14.4}=\frac{661}{sin62.4}$

$\frac{AB}{0.249}=\frac{661}{0.886}$

AB = $\frac{0.249\times661}{0.886}$

= 185.77 feet

Therefore, AB = 185.77 feet will be the answer.

4 0

3 years ago

HELP HELP <br> PLZ I WILL MARK YOU BRILL

Nikitich [7]

Answer:

1) 55 2)60-80 3)95 4)92.5(mean), 92.5 (median), 95 (mode) 5) the outlier greatly offsets the data as it is no where near the other data points.

Step-by-step explanation:

4 0

3 years ago

Let f(x) = 2x - 3. If f(x) = 15, what is x?

iragen [17]

Answer:

9=x

Step-by-step explanation:

6 0

3 years ago

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G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d

____ [38]

By definition of covariance,

$\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]$

$\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]$

We have

$\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]$

$=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

$\mathbb E[aX-b]=a\mathbb E[X]-b$

$\mathbb E[cY-d]=c\mathbb E[Y]-d$

$\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

Putting everything together, we find the covariance reduces to

$\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)$

as desired.

5 0

3 years ago