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tino4ka555 [31]
2 years ago
11

!!50 POINTS!! need it pronto!!

Mathematics
1 answer:
valentinak56 [21]2 years ago
7 0

Answer:

I would like to help but it's hard tho sorry

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Please help! B is the wrong answer!
Fynjy0 [20]
I think a is the answer 
8 0
4 years ago
Read 2 more answers
Find the explicit formula for the geometric sequence <br> 2,6,18,54
xenn [34]

Answer:

the explicit formula for the geometric sequence  2,6,18,54 is a_{n}=a_{1}.r^{n-1}

2,6,18,54

Step-by-step explanation:

In the sequence given: 2,6,18,54

The common ration is 3 because

a₁ = 2

a₂= 2*3 =6

a₃ = (2*3)*3 = 2*3^2 = 18

a₄= (2*3*3)*3 =2*3^3 = 54

Here we see for a₂ 3 has power 1, for a₃ 3 has power 2 and so on.

So, the formula will be

a_{n}=a_{1}.r^{n-1}

Here aₙ is the no of term.

a₁ is the first term of the sequence

and r is the common ratio among the sequence.

8 0
4 years ago
Read 2 more answers
Kyilah bought 41.19 grams of chili and 19.415 grams of sugar. Did Kyilah buy more chili or sugar?
Sauron [17]

Answer:

Chili I think, I don't know for certain

Step-by-step explanation:

7 0
2 years ago
Help Me Please I would appreciate it!!!!
valentina_108 [34]

9514 1404 393

Answer:

  y +2 = (1/4)(x +1)

Step-by-step explanation:

The given line is in slope-intercept form:

  y = mx + b

where the slope (m) is -4 and the y-intercept (b) is +13.

For the perpendicular line, we need a slope that is the opposite reciprocal, or ...

  -1/m = -1/(-4) = 1/4

A suitable form for the desired equation is the point-slope form:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

For m=1/4 and (h, k) = (-1, -2), the equation of the line is ...

  y +2 = (1/4)(x +1)

7 0
3 years ago
Which of the following shows that △ABD≅△CBD, when y=5?
Pavlova-9 [17]

Answer:

The correct option is;

∠ADB ≅ ∠CDB, \overline {BD} ≅ \overline {BD} and \overline {AD} ≅ \overline {CD}. So ΔABD ≅ ΔCDB by SAS

Step-by-step explanation:

The given parameters are;

The polygon given = Quadrilateral

The diagonal of the quadrilateral = BD

The length of the side AD = (2×y + 5) units

The length of the side CD = (y + 10) units

The given measure of ∠ABD = (2 × y + 25)°

The given measure of ∠CBD = 35°

When y = 5, we have by substituting the value of y into the equations representing the dimensions of the quadrilateral ABCD;

The length of the side AD = 2 × y + 5 = 2×5 + 5 = 15 units

∴ The length of the side AD = 15 units

The length of the side CD = (y + 10) units = (5 + 10) units = 15 units

∴ The length of the side CD = 15 units

The measure of ∠ABD = (2 × y + 25)° = (2 × 5 + 25)° = 35°

The measure of ∠ABD = 35°

Therefore;

∠ADB ≅ ∠CDB by substitution

\overline {BD} ≅ \overline {BD} by reflexive property

\overline {AD} ≅ \overline {CD} by substitution

∴ ΔABD ≅ ΔCBD by Side-Angle-Side rule of congruency

7 0
3 years ago
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