All categories

3 years ago

The speed of a 1200 kg car increases from 5 to 29 m/s in 12 s. What force accelerated the car?

1 answer:

5 0

Answer:I think I’m not sure But I think that the force that would be accurated the car would be friction or something like that and to solve the equation you would do f/m

Explanation:

It just makes sense

You might be interested in

A car travels 5 km towards north than turns right and travels 3km further, the car again turns right and travel 1 km and comes t

Artyom0805 [142]

The car traveled a distance of 9km and the displacement was 3km

8 0

3 years ago

What is the unit of work? Explain whether the unit of work is a fundamental uint

Levart [38]

Answer:

1)the unit of work is joule. 2)it is derived unit because it is made by two different unit force and displacement .3)

3 0

3 years ago

I need help ASAP I need to get this right plz plz plz!!!!!

Rina8888 [55]

The atomic nucleus consists of protons and neutrons.

Additional information:

Protons are positively charged particle and neutrons are negatively charged particle.

Hope this will help u...:)

3 0

3 years ago

Read 2 more answers

Which lighting direction is used to create silhouettes?

Ivahew [28]

Backlighting is used to create silhouettes

HOPED I HELPED

5 0

4 years ago

Read 2 more answers

Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the

Leona [35]

Answer:

15 deg

Explanation:

Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .

Given:

For first ball, θ1 = 75◦

initial velocity for both the balls, u = 27.2 m/s

for second ball, θ2 = ?

since distance covered by both the balls is same.

Therefore,..

R1=(u^{2} sin2\alpha _{1}) /g[/tex]

the range for the first ball

the range for the second ball

R2=(u^{2} sin2\alpha _{2}) /g[/tex]

(u^{2} sin2\alpha _{2}) /g[/tex]=(u^{2} sin2\alpha _{1}) /g[/tex]

sin2\alpha _{2})=sin2\alpha _{1})

$2\alpha _{2}$ =sin^-1(sin2\alpha _{1})

$\alpha _{2}$ =1/2sin^-1(sin2\alpha _{1})

$\alpha _{2}$ =

15 deg

8 0

4 years ago