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Gwar [14]
4 years ago
13

Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the

horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .
Physics
1 answer:
Leona [35]4 years ago
8 0

Answer:

15 deg

Explanation:

Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .

Given:

For first ball, θ1 = 75◦

initial velocity for both the balls, u = 27.2 m/s

for second ball, θ2 = ?

since distance covered by both the balls is same.

Therefore,..

R1=(u^{2} sin2\alpha _{1}) /g[/tex]

the range for the first ball

the range for the second ball

R2=(u^{2} sin2\alpha _{2}) /g[/tex]

(u^{2} sin2\alpha _{2}) /g[/tex]=(u^{2} sin2\alpha _{1}) /g[/tex]

sin2\alpha _{2})=sin2\alpha _{1})

2\alpha _{2}=sin^-1(sin2\alpha _{1})

\alpha _{2}=1/2sin^-1(sin2\alpha _{1})

\alpha _{2}=

15 deg

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b) The average x component of velocity, can be calculated applying the definition of average velocity, as follows:

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c) The found value of  avg,x is not the same as the arithmetic average of the initial and final values of vx (70 Km/h) due to the time traveled at both velocities was not the same.

If the driver had droven half of the time (1.5 h) at 50 km/h and the other half at 90 km/h, total displacement would have been as follows:

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