Answer:
It will cover a distance of 90.155 m.
Explanation:
For the first case, using the kinematic equation 3,
v^2-u^2=2as
Here v=0, u=50 km/h which is 13.88 m/s and x=10 m. so
0-(13.88)^2=2*a*10
a=9.63 m/s^2
For the second case, u=150 km/h which is 41.67 m/s.
If the acceleration is same for this case, then using the same kinematic equation.
0-(41.67)^2=2*9.63*s
s=90.155 m
brainly.com/question/13436149
#SPJ10
The object that had the most 1000 ton weight has the most momentum
A) 1 rev = 2π rad. Using this ratio, you can find the rad/s: 1160 rev/min x 2π rad/rev x 1 min/60 s = 121.5 rad/s
b) You can find linear speed from angular speed using this equation (note the radius is half the diameter given in the question): v = ωr = 121.5 rad/s x 1.175 m = 142.8 m/s
c) You can find centripetal acceleration using this equation: a = v^2/r = (142.8 m/s)^2 / 1.175 m = 17 355 m/s^2
Answer:
When the object is placed between centre of curvature and principal focus of a concave mirror the image formed is beyond C as shown in the figure and it is real, inverted and magnified.
