The difference in the pressure between the inside and outside will be 369.36 N/m²
<h3>What is pressure?</h3>
The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.
It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.
The given data in the problem is;
dP is the change in the presure=?
Using Bernoulli's Theorem;

Hence, the difference in the pressure between the inside and outside will be 369.36 N/m²
To learn more about the pressure refer to the link;
brainly.com/question/356585
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Velocity (unit:m/s) of the wave is given with the formula:
v=f∧,
where f is the frequency which tells us how many waves are passing a point per second (unit: Hz) and ∧ is the wavelength, which tells us the length of those waves in metres (unit:m)
f=1/T , where T is the period of the wave.
In our case: f=1/3
∧=v/f=24m/s/1/3=24*3=72m
Answer:
Approximately
, assuming that the gravitational field strength is
.
Explanation:
Let
denote the required angular velocity of this Ferris wheel. Let
denote the mass of a particular passenger on this Ferris wheel.
At the topmost point of the Ferris wheel, there would be at most two forces acting on this passenger:
- Weight of the passenger (downwards),
, and possibly - Normal force
that the Ferris wheel exerts on this passenger (upwards.)
This passenger would feel "weightless" if the normal force on them is
- that is,
.
The net force on this passenger is
. Hence, when
, the net force on this passenger would be equal to
.
Passengers on this Ferris wheel are in a centripetal motion of angular velocity
around a circle of radius
. Thus, the centripetal acceleration of these passengers would be
. The net force on a passenger of mass
would be
.
Notice that
. Solve this equation for
, the angular speed of this Ferris wheel. Since
and
:
.
.
The question is asking for the angular velocity of this Ferris wheel in the unit
, where
. Apply unit conversion:
.
Answer:
True
Explanation:
The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.
The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.
Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.
Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.
The final answer is -322, 320 Joules. The solution for the problem is:
The equation that must be used in this problem is:
U = mCp(Tf-Ti)
where:
U = energy released or absorbed in Joules
m = mass in kg
Cp = specific heat of material in J/kg-C
Tf = final temperature, C
Ti = initial temperature, C
Looking up the Cp of granite gives a value of 790 J/kg-C.
U = 17kg (790 J/kg-C) (21-45)
<span>U = - 322, 320 Joules (negative means heat is released)</span>