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Lapatulllka [165]
3 years ago
11

Round 0.955 inches to the nearest tenth of an inch

Mathematics
1 answer:
stellarik [79]3 years ago
7 0
The correct answer is:  
_____________________________________________________
        "1.0 inch" ;  (or, write as: "1.0 in." ; or even: "1.0 inches" .) .
____________________________________________________
Given:  "0.995 inches" ; round to the nearest TENTH of an inch.
 
(which means; round to the nearest "first decimal point" ; and to include the actual first decimal point (and that decimal point only, the "tenths place").
 
We are given the number:  "0.955" .  This is given to the nearest THOUSANDS.  

We examine the "tenths place":  "0.9" .  So we know our choices are:

"0.9" (round down to the nearest tenths place); or, "1.0" (round up to the nearest tenths place).  

            →  We examine the number: "0.955" ; and look to the next value, the "hundredths place".  
            → If that digit is 5 or greater (i.e. 5 to 9), we "round up" ; and the correct answer is:  "1.0" .  If that number is "4" or less (i.e. 0 to 4), we round down; and the correct answer is:  "0.9".
________________________________________
In the case of our give value:  "0.955" .  The digit to the right of "9" is "5" ; so, as previously mentioned, we "round up" ;  to:  "1.0".

Do not forget to include the units.
______________________________________________________
The answer is:  1.0 inches.
______________________________________________________

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3 years ago
X = 10<br><br> x = 2<br><br> x = two divided by five.<br><br> x = 11
KengaRu [80]

Answer:

x = 10

Step-by-step explanation:

You can try the answers to see which works. (The first one does.)

Or, you can solve for the variable:

Divide by 75

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Recognize that 25 = 5^2, so ...

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Equating exponents, you have

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... x = 10 . . . . . multiply by 5

_____

You can also start by taking logarithms:

... log(75) +(x/5)log(1/5) = log(3)

... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log

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... x = 10 . . . . . multiply by 5

_____

"Equating exponents" is essentially the same as taking logarithms.

5 0
3 years ago
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