Let the numbers be 7x and 4x
According to question
7x-4x =57
3x =57
X=57/3
X=19
So the numbers are
7x=7*19=133
4x=4*19=76
Y-b=mx-am
y-b-mx=am
(y-b-mx)/m=a
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Solve for h</u>
- S = 2πr² + 2πrh
- 2πrh = S - 2πr²
- h = (S- 2πr²)/(2πr)
The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have
The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have
The second sum is simply the sum of N ones:
So, the final result is
which ends the proof.