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kakasveta [241]
3 years ago
5

Find the values of x when y =1

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
Graph the rationale functions f(x)x2+3X-1/x+1 by identifying its key features.
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X^2 -11x +30 in factored form
AlladinOne [14]

Answer:

(x-5)(x-6)

Step-by-step explanation:

It would be the answer above. Hope this helps!

5 0
3 years ago
Can someone help me?
Alona [7]

Answer:

Step-by-step explanation:

its the third one

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2 years ago
206.8<br> × .42 need help I keep coming up with the wrong answer dont know what I'm doing wrong
aleksklad [387]
86.856 should be the correct answer
4 0
3 years ago
Read 2 more answers
Given that f(x)= 2x+1 and g(x)= x^2 +2x+1 find (F+g)(2). Find (F.g)(x) find f(x)/g find f(2) +g(-2)?
Pepsi [2]

Answer:

(f+g)(2) = 14

f(g(x)) = 2x^2 + 4x +3

\frac{f(x)}{g(x)} = \frac{2x+1}{x^2+2x+1}

f(2) + g(-2) = 6

Step-by-step explanation:

Function composition and transformation combines functions together using operations such as addition, subtraction, multiplication, division and substitution. To find each, perform the operation with the functions f(x) = 2x+1 and g(x) = x^2 + 2x +1.

(f+g)(x) is the functions f and g added together with 2 substituted for x.

(f+g)(x) = 2x+1 + x^2 +2x + 1 = x^2 + 4x + 2\\(f+g)(2) = 2^2 + 4(2) + 2 = 14

(f·g)(x) is function composition that means f(g(x)) or substitute g(x) into f(x).

f(g(x)) = 2(x^2+2x+1)+1 = 2x^2 + 4x+2 + 1\\f(g(x)) = 2x^2 + 4x +3

f(x) / g(x) is division of the two functions. Division can only occur with polynomials if they share the same factors or things which multiply to create them. If none are present, do not simplify.

\frac{f(x)}{g(x)} = \frac{2x+1}{x^2+2x+1}

This cannot be simplified.

f(2) + g(-2) means find the function value of f at 2 and the function value of g at -2 then add them together.

f(2)+g(-2) = 2(2)+1 + ((-2)^2+2(-2) + 1)\\f(2) + g(-2) = 5 + (4-4+1)\\f(2) + g(-2) = 5 +1 = 6

7 0
3 years ago
Read 2 more answers
Which graph represents 2x-5y &lt;15
Alinara [238K]
I don’t even know I just want to get points
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3 years ago
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