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3 years ago

Why does the fraction 20/25 not belong with 1/20, 2/3 and 5/4?

Mathematics

1 answer:

devlian [24]3 years ago

7 0

I’m not 100% sure but I think it’s because 20/25 can still be simplified further, while the other 3 can’t.

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Please help me with both questions!!!!

Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0

3 years ago

A restaurant has square dining tables.they will place table settings on each table so that there is a distance of 2 feet from ea

geniusboy [140]

The perimeter would be 9.

7 0

3 years ago

What are the zeros of the graphed function y = (x + 3)(x + 5)?

tensa zangetsu [6.8K]

Y=(x+3)(x+5)
0=(x+3)(x+5)
0=x+3
Subtract three on both sides
-3=x
0=x+5
Subtract five on both sides
-5=x
So, -3 and -5 are the zeros of the graphed function.
Hope I helped!

5 0

3 years ago

Read 2 more answers

RV=y+27 and TV=3y–17, find RV in parallelogram RSTU.<br> T<br> S<br> R<br> U<br> V

zaharov [31]

Answer:

RV = 49 units

Step-by-step explanation:

in parallelogram RSTU , the diagonals bisect each other, then

TV = RV , that is

3y - 17 = y + 27 ( subtract y from both sides )

2y - 17 = 27 ( add 17 to both sides )

2y = 44 ( divide both sides by 2 )

y = 22

Then

RV = y + 27 = 22 + 27 = 49 units

6 0

2 years ago

A car travels 14km in 25mins . Find out how far the car can travel in 5 hours if the speed remains the same ?

jekas [21]

<h3><u>Answer :- </u></h3>

168 km ...

<h3><u>Explanation :- </u></h3>

It is given that the car travels 14km in 25 minutes..

Now , assume that the distance the car travel in 5 hours be x..

Since 1 hour = 60 minutes..
5 hours = 300 minutes ..

• Thus , The two given statements are :-

14km -----------------> 25 minutes..
And, x km -------------> 300 minutes..

The distance travelled by car and the time taken by the car is directly proportional to each other....

$\frac{14}{25} = \frac{x}{300}$

$= x = 168km$

• Hence , Car can travel 168km in 5 hours ..

Hope this helps you :)

6 0

2 years ago