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3 years ago

Why does the fraction 20/25 not belong with 1/20, 2/3 and 5/4?

Mathematics

1 answer:

devlian [24]3 years ago

7 0

I’m not 100% sure but I think it’s because 20/25 can still be simplified further, while the other 3 can’t.

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The answer and explanation to question 1

xxMikexx [17]

Answer:

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

Step-by-step explanation:

The data set is split by digit. So 2|0 becomes 20. 5|5 becomes 55. Using this method, the data set is

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

7 0

3 years ago

Help me asap! I will mark you brainly and a heart tysm! :D

RideAnS [48]

The answer is A) -4/25 because when you multiply 8/15 and -3/10, you can simplify the expression to 4/5 times -1/5, which equals -4/25.

7 0

3 years ago

Read 2 more answers

Solve the equation for v <img src="https://tex.z-dn.net/?f=y%3D%5Cfrac%7B8%7D%7Bav%7D%20%2B7" id="TexFormula1" title="y=\fra

My name is Ann [436]

Answer:

$v = \dfrac{8}{a(y - 7)}$

Step-by-step explanation:

$y = \dfrac{8}{av} + 7$

Subtract 7 from both sides.

$y - 7 = \dfrac{8}{av}$

Multiply both sides by v.

$v(y - 7) = \dfrac{8}{a}$

Multiply both sides by 1/(y - 7).

$v = \dfrac{8}{a(y - 7)}$

3 0

3 years ago

A reflection is a transformation that maps point Q in a figure over a line, AB, such that for point C at th intersection of AB a

Goshia [24]

Answer: $\overline{QC}\cong\overline{Q'C'}$ and $\angle{ACQ}$ is a right angle .

Step-by-step explanation:

Given : A reflection is a transformation that maps point Q in a figure over a line, AB, such that for point C at the intersection of AB and QQ'.

We know that reflection creates a image equidistant from the line of reflection.

Thus, $\overline{QC}\cong\overline{Q'C'}$

Also in reflection , a line drawn from the point is perpendicular to the line of reflection.

Therefore, $\angle{ACQ}$ is a right angle

5 0

3 years ago

C= 44+(p-1)(32)/2 what is p?

Vilka [71]

Answer: $\bold{p=\dfrac{c-28}{16}}$

Step-by-step explanation:

$c=44+\dfrac{(p-1)(32)}{2}\\\\c=44+(p-1)(16)\quad \rightarrow\quad \text{simplified}\ (32\div2=16)\\\\c=44+16p-16\quad \rightarrow\quad \text{distributed 16 into p - 1}\\\\c=28+16p\quad \rightarrow\quad \text{added like terms (44 - 16)}\\\\c-28=16p\quad \rightarrow\quad \text{subtracted 28 from both sides}\\\\\dfrac{c-28}{16}=p\quad \rightarrow\quad \text{divided 16 from both sides}$

6 0

3 years ago