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posledela
3 years ago
8

Which number comes first if the numbers 2.001, 0.0035, 0.0005, 4.56094 are arranged in order from most to fewest significant dig

its?
A. 0.0005
B. 0.0035
C. 2.001
D. 4.56094
Mathematics
2 answers:
deff fn [24]3 years ago
4 0

Answer:

D.

Step-by-step explanation:

PLZ give me brainliest

grigory [225]3 years ago
4 0
D. 4.56094 I hope that helps you good luck
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1. What is the equation of the line that passes through (2, -1) and whose y-intercept is 5?
weqwewe [10]
1. Selection B is the only equation satisfied by both (0, 5) and (2, -1).

2. Selection D is the only one with a slope of 5/2.
6 0
3 years ago
The density d of a substance is given by the formula d=mV, where m is its mass and V is its volume. Solve the formula for m.
NikAS [45]

Answer:m=d/V

Step-by-step explanation:

To solve for m, you must divide V from each side. Leaving you with m=d/V. Hope this helped:)

5 0
3 years ago
Read 2 more answers
Use slopes and y-intercepts to determine if the lines 6x+y=−1 and −2x−5y=1 are parallel.
kobusy [5.1K]

Answer:

The two lines are not parallel.

Step-by-step explanation:

Every linear equation follows this structure:

y = mx + b

y is the y value

x is the x value

m is the gradient/slope of the line

b (or sometimes c) is the y-intercept of the line

Firstly, we have to get the y term on one side by itself.

6x + y = -1

-6x        -6x

y = -6x - 1

-2x -5y = 1

+2x         +2x

-5y = 2x + 1

Secondly, we make it so the y term is just the y value.

The first equation is already like this, so we don't need to do anything to that.

-5y = 2x + 1

÷ -5  ÷ -5

y = (2x + 1) / -5

This can be expanded and simplified to:

y = -2/5x - 1/5

Thirdly, we have to compare the slopes and y-intercepts.

y = -6x - 1

y = 2/5x - 1/5

If the slopes are the same and the y-intercepts are different, they are parallel. However, the slopes are different, therefore they are not parallel.

7 0
3 years ago
What is the area of a sector of a circle with a radius of 8 inches and formed by a central angle that measures 60°?
Sergeu [11.5K]
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta\pi r^2}{360}\qquad 
\begin{cases}
r=radius\\
\theta=\textit{angle in degrees}
\end{cases}
7 0
3 years ago
a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora
Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.

  • When the number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

The equation form is 6x+y=3500 ..........[1]

  • When the number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

The equation form is 4x+y=2400  ........[2]

Solving equation [1] and [2]

Subtract equation [2] from [1],

6x+y-4x-y=3500-2400

2x=1100

x=550

Put value in [1],

6(550)+y=3500

3300+y=3500

y=200

Therefore, The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

8 0
3 years ago
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