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sergeinik [125]
3 years ago
11

What is the area of the polygon given below?

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

diện tích đa giác trong hình là :

186 cm2

Step-by-step explanation:

hãy tách hình đa giác trên thành 4 hình chữ nhật và tính diện tích từng hình chữ nhật

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Find the slope of the line that passes through the points (3, 6) and (5, 3).
FromTheMoon [43]
The slope of the line is -3/2
3 0
3 years ago
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A region with a 10-mile radius has a population density of about 1500 people per square mile. Find the number of people who live
riadik2000 [5.3K]

The total population in the region is 942000

<u>Step-by-step explanation:</u>

Radius of the region= 10 miles

Population density= 1500 per square mile

Area of the region = 2π(r x r)

= 2π(10 x 10)

=2(3.14) (100)

= 628 square miles

Population = 1500 x 628

= 942000

The total population in the region is 942000

6 0
3 years ago
Can someone help me i am confused
hammer [34]

Answer:

3. 2

4. f(n) = 3 + 4(n - 1)

Step-by-step explanation:

3. The general term of the arithmetic sequence is given by:

                                    A(n) = - 14 + (n - 1)(2)

To find the ninth term of this arithmetic sequence, just put $ n = 9 $ in the general term.

∴ A(9) = - 14 + (9 - 1)(2) = - 14 + 8(2) = -14 + 16 = 2.

Therefore the ninth term in the arithmetic sequence is two.

4. To know which expression represents the given sequence, substitute different values for $ n $ to conclude.

In Option A, f(n) = 4 + 3(n - 1). Substitute n = 1.

We get f(1) = 4 + 3(0) = 4. This is not the first term in the sequence and can be eliminated.

In Option B, f(n) = 4 + 3n. Substitute n = 1.

We get f(1) = 4 + 3(1) = 7, not 3 so can be eliminated.

Similarly in Option C, we get 7 and could be eliminated.

In Option D, f(n) = 3 + 4(n - 1). Substitute n = 1.

We get f(1) = 3 + 4(1 - 1) = 3, which is the first term in the sequence.

Similarly, f(2) = 3 + 4(2 - 1) = 3 + 4 = 7.

Substitute n = 3, 4 to get other terms as well.

So, we say f(n) = 3 + 4(n - 1) is the representation of the given arithmetic sequence.

5 0
3 years ago
Assume, for the sake of this question, that the data were collected through a well-designed, well-implemented random sampling me
amid [387]

Answer:

Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.

Step-by-step explanation:

The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.

This means that at the null hypothesis we test if the proportion is at least 60%, that is:

H_{0}: p \geq 0.6

And the alternate hypothesis is:

H_{a}: p < 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that:

\mu = 0.6

\sigma = \sqrt{0.6*0.4}

Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.

This means that n = 575, X = \frac{338}{575} = 0.5878

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}

z = -0.6

Pvalue of the test and decision:

We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.

Looking at the z-table, z = -0.6 has a pvalue of 0.2743.

Since 0.2743 > 0.1, the threshold probably was met.

3 0
3 years ago
State whether f is a function
Alenkinab [10]
<h2>Answer:</h2>

y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function

<h2>Step by step solution:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function f has an inverse function if and only if there is no any horizontal line that intersects the graph of f at more than one point. So the function is called one-to-one. The graph of f is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find f^-{1}(x):

f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}

and this is not a function because there are elements in the set of inputs that match with two elements in the set of outputs.

5 0
3 years ago
Read 2 more answers
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