It's false. It's a product so...
Derivative of the first TIMES the second PLUS derivative of second TIMES the first.
Derivative of the first (x^3) = 3x^2
Times the second = 3x^2 * e^x
Derivative of the second = e^x (remains unchanged)
Times the first = e^x * x^3
So the answer would be (3x^2)(e^x) + (e^x)(x^3)
which can be factorised to form x^2·e^x(3 + x)
M is 1
if you subtract 1/3 from 1 (3/3), it is 2/3.
3 - 1 = 2
Answer:
4.35pm is the later time, both buses were together back at the depot.
Reasons;
As bus b did not return his return route until 35 minute after departure.
We can say this was a return route taking 35 minute as the question does not point out length of time getting back. We therefore state it is a return route in the workings to explain how we found the answer.
Step-by-step explanation:
4.00 + 0.35 = 4.35 = b
4.00 + 0.15 = 4.15 = a
4.35 is the later time.
